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Vinil7 [7]
3 years ago
14

What is a Hypothesis?

Chemistry
1 answer:
Elenna [48]3 years ago
4 0

Answer:

A hypothesis is a claim you make about what you think is going to happen in an experiment.

Hope This Helps

<3

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When heated, solid copper(ii) carbonate decomposes to solid copper(ii) oxide and carbon dioxide gas. give the balanced chemical
RideAnS [48]
CuCO3(s) -----T---> CuO(s) + CO2(g)

:-) ;-)
8 0
3 years ago
In a water molecule, the shared electrons spend more time around
Gekata [30.6K]
Probably very negative or sightless negative
6 0
3 years ago
What is the oxidation number of cl− in the perchlorate ion
Yuri [45]

Answer:

The answer is: +7

Explanation:

Oxidation state or oxidation number of an element is the hypothetical charge on an element that forms completely ionic bonds. The oxidation number represents the number of electrons lost or gained by that element.

Perchlorate ion is a molecule with a chemical formula: ClO₄⁻

The oxidation state of oxygen in ClO₄⁻ = -2,

the total charge on the ClO₄⁻ molecule = -1,

let the oxidation state of chlorine be x

<u><em>As the sum of oxidation states of all elements in a molecule is equal to the total charge on the molecule.</em></u>

⇒ oxidation state of chlorine + oxidation state of oxygen × 4 = total charge on the molecule

⇒ x + (-2) × 4 = -1

⇒ x + (-8) = -1

⇒ x = -1 + 8 = +7

⇒<u> </u><u>x = +7</u>

<u>Therefore, the oxidation state of chlorine in the perchlorate ion (ClO₄⁻): x = +7</u>

5 0
3 years ago
Enough of a monoprotic acid is dissolved in water to produce a 1.64 M solution. The pH of the resulting solution is 2.82 . Calcu
Lady bird [3.3K]

Answer:

Ka = 1.39x10⁻⁶

Explanation:

A monoprotic acid, HX, will be in equilibrium in an aqueous medium such as:

HX(aq) ⇄ H⁺(aq) + X⁻(aq)

<em>Where Ka is:</em>

Ka = [H⁺] [X⁻] / [HX]

<em>Where [] is the molar concentration in equilibrium of each specie. </em>

The equilibrium is reached when some HX reacts producing H+ and X-, that is:

[HX] = 1.64M - X

[H⁺] = X

[X⁻] = X

As pH is 2.82 = -log [H⁺]:

[H⁺] = 1.51x10⁻³M:

[HX] = 1.64M - 1.51x10⁻³M = 1.638M

[H⁺] = 1.51x10⁻³M

[X⁻] = 1.51x10⁻³M

And Ka is:

Ka = [1.51x10⁻³M] [1.51x10⁻³M] / [1.638M]

<h3>Ka = 1.39x10⁻⁶</h3>
6 0
3 years ago
You and your lab partner are asked to determine the density of an aluminum bar. The mass is known accurately to 4 significant fi
zmey [24]

Answer:

Average density for method A = 2.4 g/cm³

Average density for method B = 2.605 g/cm³

Explanation:

In order to calculate the average density for each method, we need to add the data for each method, and then divide the result by the number of measurements (in this case is 4 for both methods):

  • For Method A:

Σ = 2.2 + 2.3 + 2.7 + 2.4 = 9.6

Average = 9.6/4 = 2.4 g/cm³

  • For Method B:

Σ = 2.603 + 2.601 + 2.605 + 2.611 = 10.420

Average = 10.420/4 = 2.605 g/cm³

5 0
3 years ago
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