2. You know that $y=\frac{sinx}{cosx}$ with $cosx\neq 0$ , because the division by zero is not defined. So , $cosx=0$ for $\frac{(2n+1)\pi}{2}$ where $n$ is a integer number.

3. Then, to find the domain of the function given in the problem, you must make $\frac{x}{8} \neq \frac{k\pi}{2} \\ x\neq 4k\pi$

Where $k$ is odd number.

4. Therefore:

$x\neq 4\pi (2n+1)$

5. Finally, the domain is: $4\pi (2n+1)$

The answer is: $4\pi (2n+1)$

5 0

4 years ago

Read 2 more answers

2/3x+5=7/3 <br> How do you solve this!

TEA [102]

You want to start by subtracting 5 from both sides to get 2/3x=-8/3 then cross multiply to get whole numbers which is 6=-24x then your gonna want to isolate the variable so divide both sides by -24 to get 6/-24=x then you can simplify to x=-1/4

4 0

2 years ago