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2 years ago

9

746/40

lass="latex-formula">

1 answer:

jolli1 [7]2 years ago

5 0

Answer:

373

Step-by-step explanation:

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solve quadratic by taking square roots. as=a,-a where a and -a the values you found when when solving. Round to nearest tenth. 2

attashe74 [19]

Answer:

8.1

Step-by-step explanation:

2x^2 -9 = 121

+9 +9

2x^2 = 130

/2 /2

x^2 = 65

x= sqrt (65)

x= 8.06225...

x = 8.1

6 0

2 years ago

The drawing below is an example of what kind of perspective?

sladkih [1.3K]

Answer:

Two-point

Step-by-step explanation:

"Orthogonal" lines intersect the horizon at two points. This is an example of 2-point perspective.

3 0

2 years ago

Dave buys 4 slices of one kind. He pays $6.00.

s344n2d4d5 [400]

Okay, so if Dave buys 4 slices of one kind and pays $6.00 $6 / 4 = $1.50 per slice So the correct answer is whichever pizza is $1.50 per slice. Hope that helps!

3 0

2 years ago

Anton is drawing a flag of Switzerland, which has a square shape, for a school project. If he wants the flag to have sides that

sergejj [24]

Answer:

It should be A

Step-by-step explanation:

Because there are 4 sides and if you multiply 16x4 that will give you 64

it simple good luck :)

4 0

2 years ago

Read 2 more answers

The area of a right triangle is sixty square centimetres. Its base is one centimetre less than twice its height. If the base and

NemiM [27]

Answer:

5. None of the above

Step-by-step explanation:

We have this information:

A = 60 cm2

b = 2*h - 1

Let's find out b and h:

The equation of the are of a triangle is A = (b*h)/2, if we replace it with our information, we have

$60 = ((2*h - 1) * h)/2\\ 120 = 2*h^2 - h\\ 0 = 2*h^2 - h - 120$

Let's find h with the quadratic formula:

$\fbox {Quadratic formula:} \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$h = \frac{-(-1)\pm\sqrt{(-1)^2-4*2*(-120)}}{2*2} = \frac{1\pm\sqrt{961}}{4} = \frac{1\pm\ 31}{4}$

h = 8 or h = -7.5

But h represents the height of the triangle, so it has to be a positive number, that's h = 8.

If we replace this in the equation we had for b, we have that b = 2*8 - 1 = 15.

Now we can calculate the hypotenuse with the Pythagorean equation

$\fbox {Pythagorean equation:}$ <em>The square of the length of the hypotenuse (the side opposite the right angle) of a right triangle is equal to the sum of the squares of the two legs (the two sides that meet at a right angle). </em>

The base and the height are our legs. We will use "H" for the hypotenuse

$H^2 = b^2 + h^2 = 15^2 + 8^2 = 289\\ H = \sqrt {289} = 17$

H = 17

If we decrease the base and the height by 2 centimeters, we have

b' = 15 - 2 = 13 and h' = 8 - 2 = 6

With this, let's calculate the new hypotenuse:

$H'^2 = b'^2 + h'^2 = 13^2 + 6^2 = 205\\ H' = \sqrt {205} \approx 14.3$

$H' \approx 14.3$

So, the hypotenuse decreases $H - H' \approx 17 - 14.3 = 2.7$

3 0

2 years ago