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Greeley [361]
3 years ago
10

Consider these ground-state ionization energies of oneelectron species:

Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
3 0

Answer:

Explanation:

general expression for the ionization energy of any one-electron species.

=  z² x ground level energy / n²

z is atomic no , n is energy level .

ground level energy of

 H = 1.31 x 10³ kJ/mol

He⁺ = 2² x  1.31 x 10³ kJ/mol  =  5.24 x 10³ kJ/mol

Li²⁺ = 3² x  1.31 x 10³ kJ/mol   = 1.18 x 10⁴ kJ/mol

b ) the ionization energy of B⁴⁺.

= 5² x 1.31 x 10³ kJ/mol  = 32.75 x 10³ kJ/mol  

c )  minimum energy required to remove the electron from the n = 3 level of He⁺ per mole

= 5.24 x 10³ / 9  kJ/mol

= 5.82 x 10² kJ/mol

= 5.82 x 10² x 10³ / 6.02 x 10²³ J

.9667 X 10⁻¹⁸ J

= .9667 X 10⁻¹⁸ / 1.6 X 10⁻¹⁹ eV

= 6.042 eV

= 1237.5 / 6.042

= 204.82 nm

=

d )

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Answer;
A decrease in the vapor pressure of the liquid. 

Dissolving a solute such as potassium hydroxide in a solvent such as water results in a decrease in the vapor pressure of the liquid. 

Explanation; 
The vapor pressure of a liquid is the equilibrium of a vapor above its liquid.
In other words it is the pressure of the vapor resulting from the evaporation of a liquid above a given sample of the liquid in a closed container.
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How many moles of nitrogen dioxide gas will be produced if 25.0 ml of 2M nitric acid react?
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Answer:

0.025 moles of NO₂  will produced

Explanation:

Given data:

Moles of NO₂ formed = ?

Volume of HNO₃ = 25.0 mL

Molarity of HNO₃ = 2 M

Solution:

Chemical equation:

Cu + 4HNO₃   →        Cu(NO₃)₂ + 2NO₂ + 2H₂O

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Now we will compare the moles of HNO₃  with NO₂  from balance chemical equation.

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                                      4                :            2

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0.025 moles of NO₂  will produced.

                                     

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Answer:

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From the question given above, the following data were obtained:

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To know the name of the element with the above electronic configuration, we shall determine the atomic number of the element. This can be obtained as follow:

Number of electrons = 2 + 2 + 6 + 2 + 6 + 2 + 10 + 6 + 1

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Next, we shall determine the number of protons. This can be obtained as follow:

From the question given above, the element has no charge. Hence the element contains equal numbers of protons and electrons.

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