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Rzqust [24]
3 years ago
15

A school psychologist notes that the average number of times that students are disruptive during class is 1.4 [μ=1.4] times per

day. Following recent classroom policy changes, the psychologist tests if the number of disruptions during class has changed. He records the following number of disruptions observed during a class day: 2, 4, 3, 5, 1, 1, and 4.
A. Test the hypothesis that the number of complaints has increased or decreased using a .05 level of significance.
B. Compute effect size using estimated Cohen's d.
Mathematics
1 answer:
marta [7]3 years ago
5 0

Answer:

Reject the Null ;

0.928

Step-by-step explanation:

Given the data: 2, 4, 3, 5, 1, 1, 4

Sample mean = (2 + 4 + 3 + 5 + 1 + 1 + 4) / 7 = 2.857

Standard deviation, s = 1.57 ( using calculator)

The hypothesis :

H0 : μ = 1.4

H1 : μ ≠ 1.4

Since sample size is small, use T test

Test statistic :

Tstatistic = (x - μ) / s/sqrt(n)

Tstatistic = (2.857 - 1.4) / 1.57/sqrt(7)

Tstatistic = 1.457 / 0.593 = 2.455

Two tailed test at α = 0.05

Tcritical at df = 7-1 = 6 ; α = 0.05 = 2.447

Tstatistic > Tcritical ; reject the null

Since ;

2.455 > 2.447 ; we reject the null ;

There is significam evidence that Number of complaints has changed.

Effect size ;

d = (x - μ) / s

d = (2.857 - 1.4) / 1.57

d = 1.457 / 1.57

d = 0.928

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djyliett [7]

Slope = (10 - 5)/(-9 + 15) = 5/6

y = mx + b where m = slope and b = y-intercept

b = y - mx

b = 5 - (5/6) (-15)

b = 5 +12.5

b = 17.5

Equation y = 5/6 x + 17.5

Y-intercept = 17.5

X-intercept when y = 0

So

5/6 x + 17.5 = 0

5/6 x = -17.5

x = (-17.5) (6/5)

x = -21

Answer

Y intercept (0, 17.5 )

X intercept (-21 , 0)

3 0
3 years ago
Before the distribution of certain statistical software, every fourth compact disk (CD) is testedfor accuracy. The testing proce
pishuonlain [190]

Answer:

P(T∩E) = 0.017

Step-by-step explanation:

Since every fourth CD is tested. Thus if T is the event that represents 4 disks being tested,

P(T) = 1/4 = 0.25

Let Fi represent event of failure rate. So from the question,

P(F1) = 0.01 ; P(F2) = 0.03 ; P(F3) =0.02 ; P(F4) = 0.01

Also Let F'i represent event of success rate. And we have;

P(F'1) = 1 - 0.01 = 0.99 ; P(F'2) = 1 - 0.03 = 0.97; P(F'3) = 1 - 0.02 = 0.98; P(F'4) = 1 - 0.01 = 0.99

Since all programs run independently, the probability that all programs will run successfully is;

P(All programs to run successfully) =

P(F'1) x P(F'2) x P(F'3) x P(F'4) =

0.99 x 0.97 x 0.98 x 0.97 = 0.932

Now, that all 4 programs failed will be = 1 - 0.932 = 0.068

Let E be denote that the CD fails the test. Thus P(E) = 0.068

Now, since testing and CD's defection are independent events, the probability that one CD was tested and failed will be =P(T∩E) = P(T) x P(E)= 0.25 x 0.068 = 0.017

8 0
3 years ago
Tyler used 6 gallons of paint to paint 4/7 of a fence. How many gallons will it take to paint the whole fences
vredina [299]

Answer:

Step-by-step explanation:

(6 gal)/(4/7 fence) = (21/2 gal)/fence = (10.5 gal)/fence

5 0
2 years ago
Help me on this please appreciate it
lakkis [162]

Answer:

A

Step-by-step explanation:

reflections don't change size or shape just like mirrors

3 0
2 years ago
Tess needs to buy sand for her children’s playground. The sand costs $8 per ton, and there is a delivery cost of $50 with each o
Butoxors [25]

Answer:

All positive rational numbers greater than 50

Step-by-step explanation:

Since the delivery cost is fixed per trip, the cost incurred can be represented by the equation

y(x)=8x+50 so in case Tess wants only 1 tone, the cost will be y(x)=8(1)+50=58

Therefore, it's proper to conclude that all numbers in the possible range are positive rational numbers greater than 50

6 0
2 years ago
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