Vertices (3,0),(-3,0) co-vertices (0,-5),(0,5)
transverse axis (line passing vertices) is on(or parallel to) x-axis then formula is
(x-h)^2/a^2 - (y-k)^2/b^2 = 1
..notice.. x^2 is on positive / y^2 is on negative
center (h,k) is midway between vertices = (0,0)
we have h = k = 0 and now formula is
x^2/a^2 - y^2/b^2 = 1
a is the distance from a vertex to center = 3
b is the distance from a co-vertex to center = 5
the formula is
x^2/3^2 - y^2/5^2 = 1 ... answer is the 1st
Answer:
f=c+2
Step-by-step explanation:
Answer:
120 degrees
Step-by-step explanation:
<span>V=L*H(A+B)/2 i think the answer is 103.5</span>
Answer:
-2.35
Step-by-step explanation:
I'm not 100% Sure if that's correct but I'm pretty sure it is!
