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sattari [20]
3 years ago
15

Atoms of the element beryllium would most likely behave similar to the way _______ behaves.

Chemistry
2 answers:
lubasha [3.4K]3 years ago
3 0
It's b. calcium 
because the outer electron structure in all of that element is similar, they have the same chemical and physical properties.<span />
tatiyna3 years ago
3 0

<u>Answer:</u> The correct answer is Option B.

<u>Explanation:</u>

Beryllium is the 4th element of the periodic table having electronic configuration 1s^22s^2. This element belongs to Group 2 of the periodic table.

Elements that belong to same group show similar chemical properties because they have same number of valence electrons.

For the given options:

<u>Option A:</u> Hydrogen

This element belong to group 1 of the periodic table.

<u>Option B:</u> Calcium

This element belong to group 2 of the periodic table. Thus, this will show similar chemical properties to beryllium.

<u>Option C:</u> Lithium

This element belong to group 1 of the periodic table.

<u>Option D:</u> Boron

This element belong to group 13 of the periodic table.

Hence, the correct answer is Option B.

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Two 10g blocks, one of copper and one of iron, were heated from 300 K to 400K (a temperature difference of 100 K).
12345 [234]

1) 385 J

2) 450 J

Explanation:

1)

The amount of energy that must be absorbed by a certain substance in order to increase its temperature by \Delta T is given by the equation:

Q=mC\Delta T

where

m is the mass of the substance

C is its specific heat capacity

\Delta T is the increase in temperature of the substance

For the block of copper in this problem, we have:

m = 10 g is the mass

C=0.385 J/gK is the specific heat capacity of copper

\Delta T=400-300 = 100 K is the change in temperature

So, the energy absorbed by the block of copper is

Q=(10)(0.385)(100)=385 J

2)

Similarly for the block of iron, the energy absorbed by the iron is given by

Q=mC\Delta T

where

m is the mass of the block of iron

C is its specific heat capacity of iron

\Delta T is the increase in temperature of the block

Here we have:

m = 10 g is the mass of the block

C=0.450 J/gK is the specific heat capacity of iron

\Delta T=400-300 = 100 K is the change in temperature

So, the energy absorbed by the block of iron is

Q=(10)(0.450)(100)=450 J

6 0
3 years ago
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