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3 years ago

What is the average salinity of ocean water 1. 0.345 g/kg 2. 3.45 g/kg 3. 34.5 g/ml 4. 345 g/ml?

1 answer:

3 0

Alright so we know that to the closest whole number, that for every 1 litre (1000 mL) of seawater there are 35 grams of salts.

Thus the OPTION 3 would be the closest 34.5 g/ml

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When the glucose transport maximum is reached, _______.?

n200080 [17]

Glucose is extracted in the urine and all of the glucose is reabsorbed.

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3 years ago

WILL GIVE BRAINLIEST Explain why HS2 has a bent geometry, while BeH2 has a linear geometry.

Natali5045456 [20]

Answer:

H2S has a bent geometry, while BeH2 has a linear geometry because: presence of lone pair in H2S

Absence of Lone pair in BeH2

Explanation:

Structure of H2S :

Atomic number of S = 16 = 1s(2 )2s(2) 2p(6) 3s(2 )3p(4)

Outer most shell has 6 electron

Valence electron (Involved in bonding) = 6

Out of these 6 electrons ,

2 electrons are formed in bonding with Hydrogen

Rest 4 are non- bonding and present as lone - pair

H2S exist - sp3 hybridisation

There are 2-Lone pair on S in H2S (look at the image attached)

Structure of H2S :

Atomic number of Be = 4 = 1s(2 ) 2s(2)

Valence electron (Involved in bonding) = 2

These 2- electron are involved in bonding with two Hydrogen and form liner shape.*Form sp - hybridized

Hence shape is linear because it has non - lone pair.

VSEPR : According to this theory lone pair causes repulsion to the bond and cause unstability in the molecule.

Hence the bonds shifts away from lone pairs . This is why H-S bonds in H2S shifts way from lone pair

5 0

3 years ago

What is true of all mass and volume of all floating objects

GarryVolchara [31]

If the density is higher than water than the object will sink

5 0

3 years ago

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Consider the reaction. PCl5(g)↽−−⇀PCl3(g)+Cl2(g) K=0.042 The concentrations of the products at equilibrium are [PCl3]=0.18 M and

tatyana61 [14]

Answer: The equilibrium concentration of $PCl_5$ is 1.285 M.

Explanation:

The chemical equation for the decomposition of phosphorus pentachloride follows:

$PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)$

The expression for equilibrium constant is given as:

$K_c=\frac{[PCl_3][Cl_2]}{[PCl_5]}$

We are given:

$K_c=0.042$

$[PCl_3]=0.18M$

$[Cl_2]=0.30M$

The concentration of solid substances are taken to be 1. Thus, they do not appear in the equilibrium constant expression.

Putting values in above equation, we get:

$0.042=\frac{0.18\times 0.30}{[PCl_5]}$

$[PCl_5]=1.285$

Hence, the equilibrium concentration of $PCl_5$ is 1.285 M.

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3 years ago

Use the periodic table to calculate the molar mass of each of the following compounds. Give your answer to the correct number of

Musya8 [376]

1) Answer is: molar mas of ammonia is 17.031 g/mol.

M(NH₃) = Ar(N) + 3 · Ar(H) · g/mol.

M(NH₃) = 14.007 + 3 · 1.008 · g/mol.

M(NH₃) = 17.031 g/mol.

2) Answer is: molar mas of lead(II) chloride is 278.106 g/mol.

M(PbCl₂) = Ar(Pb) + 2 · Ar(Cl) · g/mol.

M(PbCl₂) = 207.2 + 2 · 35.453 · g/mol.

M(PbCl₂) = 278.106 g/mol.

3) Answer is: molar mas of acetic acid is 60.052 g/mol.

M(CH₃COOH) = 2 · Ar(C) + 2 · Ar(O) + 4 · Ar(H) · g/mol.

M(CH₃COOH) = 2 · 12.0107 + 2 · 15.9994 + 4 · 1.008 · g/mol.

M(CH₃COOH) = 60.052 g/mol.

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3 years ago

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