Hi there
First find the monthly payment of each offer to see which monthly payment is lower
The formula of the present value of annuity ordinary is
Pv=pmt [(1-(1+r/k)^(-kn))÷(r/k)]
Pv present value
PMT monthly payment
R interest rate
K compounded monthly 12
N time
Solve the formula for PMT
PMT=pv÷[(1-(1+r/k)^(-kn))÷(r/k)]
Bank F
PMT=16,200÷((1−(1+0.057÷12)^(
−12×8))÷(0.057÷12))
=210.53
Bank G
PMT=16,200÷((1−(1+0.062÷12)^(
−12×7))÷(0.062÷12))
=238.21
From the above the monthly payment of bank f is lower than the bank g
And since the lifetime of bank g is lower than bank f the answer is
b. Yvette should choose Bank F’s loan if she cares more about lower monthly payments, and she should choose Bank G’s loan if she cares more about the lowest lifetime cost.
Good luck!
If they sold 89 calendars over 4 weeks, the 'equation' would look like (x = average calendars sold over 4 weeks):

If you solve it, you get:

Which is equal to
22.25. Hope this helps!
Answer:
a) 1/2
b) 250
Step-by-step explanation:
The start of the question doesn't matter entirely, although is interesting to read. What we are trying to do is find the value for
such that
is maximized. Once we have that
, we can easily find the answer to part b.
Finding the value that maximizes
is the same as finding the value that maximizes
, just on a smaller scale. So, we really want to maximize
. To do this, we will do a trick called completing the square.
.
Because there is a negative sign in front of the big squared term, combined with the fact that a square is always positive, means we need to find the value of
such that the inner part of the square term is equal to
.
.
So, the answer to part a is
.
We can then plug
into the equation for p to find the answer to part b.
.
So, the answer to part b is
.
And we're done!
Asked and answered elsewhere.
brainly.com/question/10629871How do you calculate it? You start by expressing the density in the units you have. Then you multiply by appropriate conversion factors to get to the units you want. Treat units as though they were any other variable. A value cancels that appears in both the numerator and denominator of a fraction.
I think (0,0) is the only one that starts at 0 for both x and y and stay the same if the add the 3 to x and 6 to y.