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Gala2k [10]
3 years ago
7

The radius of the aorta is about 1 cm and the blood flowing through it has a speed of about 30 !" ! . Calculate the average spee

d of the blood in the capillaries given the total cross section of all the capillaries is about 2000 !"!
Physics
1 answer:
Julli [10]3 years ago
4 0

Answer:

The average speed of the blood in the capillaries is 0.047 cm/s.

Note: The question is incomplete. The complete question is as follows:

The radius of the aorta is about 1 cm and the blood flowing through it has a speed of about 30 cm/s. Calculate the average speed of the blood in the capillaries given the total cross section of all the capillaries is about 2000 cm².

Explanation:

From the given values:

radius of the aorta, r₁ = 1 cm

speed of blood, v₁ = 30 cm/s

Area of the aorta, A₁ = πr₁² where π = 3.142

Area of aorta = 3.142 × (1)² = 3.142 cm²

Area of the capillaries, A₂ = 2000 cm²

let the average speed of the blood in the capillaries = v₂

From the continuity equation of fluid flow, the product of cross-sectional area of the pipe and the fluid speed at any point along the pipe is always constant. In formula, A₁v₁ = A₂v₂

Using the continuity equation, the average the average speed of the blood in the capillaries can be calculated thus:

A₁v₁ = A₂v₂

v₂ = (A₁v₁) / (A₂)

v₂ = (3.142 x 30) / (2000)

v₂ = 0.047 cm/s

Therefore, the average speed of the blood in the capillaries is 0.047 cm/s.

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The product label which Mateo should place in the marked cell is that it: B. provides electrical energy.

<h3>What is a product label?</h3>

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4 0
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If the rectangular barge is 3.0 m by 20.0 m and sits 0.70 m deep in the harbor, how deep will it sit in the river?
leva [86]

The harbour contains salt water while the river contains fresh water. So assuming that the densities of fresh water and salt water are:

density (salt water) = 1029 kg / m^3

density (fresh water) = 1000 kg / m^3

The amount of water (in mass) displaced by the barge should be equal in two waters.

mass displaced (salt water) = mass displaced (fresh water)

Since mass is also the product of density and volume, therefore:

<span>[density * volume]_salt water = [density * volume]_fresh water                 ---> 1</span>

 

First we calculate the amount of volume displaced in the harbour (salt water):

V = 3.0 m * 20.0 m * 0.70 m

V = 42 m^3 of salt water

Plugging in the values into equation 1:

1029 kg / m^3 * 42 m^3 = 1000 kg/m^3 * Volume fresh water

Volume fresh water displaced = 43.218 m^3

 

Therefore the depth of the barge in the river is:

43.218 m^3 = 3.0 m * 20.0 m * h

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3 years ago
If the half-life of tritium (hydrogen-3) is 12.3 years, how much of
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We're given the half life of Tritium to be 12.3 years. In order to find out the amount of substabce remaining:

Let's first find how many 'half lives' are in 250 years.

n =  \frac{250}{12.3}  = 20.325

Now what is half life? It means the time taken for a given quantity of an element to lose half it's mass.

So in 12.3 years we can find that The amount of 250 g of Tritium will be 250/2 = 125 g. In 24.6 years we'll have 125/2 = 62.5 g

So now we can devise a formula:

m =  \frac{original \: amount}{ {2}^{n} }

Where m is the remaining amount and n is th number of half lives in the time given.

Using this formula we can calculate:

m =  \frac{10}{ {2}^{20.325} }

Doing this calculation we get:

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2. Lenses such as those in microscopes and telescopes depend on which property of<br><br> light?
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The eyepiece comprises a converging lens that is a magnifying lens. The lens has a short focal length,

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In lenses such as those in microscopes and telescopes, the objective forms an image with the following features:

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3 years ago
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