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Morgarella [4.7K]
3 years ago
14

If the half-life of tritium (hydrogen-3) is 12.3 years, how much of

Physics
1 answer:
tatyana61 [14]3 years ago
4 0

Answer:

0.0000076 grams

Explanation:

We're given the half life of Tritium to be 12.3 years. In order to find out the amount of substabce remaining:

Let's first find how many 'half lives' are in 250 years.

n =  \frac{250}{12.3}  = 20.325

Now what is half life? It means the time taken for a given quantity of an element to lose half it's mass.

So in 12.3 years we can find that The amount of 250 g of Tritium will be 250/2 = 125 g. In 24.6 years we'll have 125/2 = 62.5 g

So now we can devise a formula:

m =  \frac{original \: amount}{ {2}^{n} }

Where m is the remaining amount and n is th number of half lives in the time given.

Using this formula we can calculate:

m =  \frac{10}{ {2}^{20.325} }

Doing this calculation we get:

m = 0.0000076 \: g

As we can see a very small value remains.

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Light bulb 1 operates with a filament temperature of 3000 K, whereas light bulb 2 has a filament temperature of 2000 K. Both fil
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Answer:

A₁/A₂ = 0.44

Explanation:

The emissive power of the bulb is given by the formula:

P = σεAT⁴

where,

P = Emissive Power

σ = Stefan-Boltzman constant

ε = Emissivity

A = Surface Area

T = Absolute Temperature of Surface

<u>FOR BULB 1:</u>

Since, emissivity and emissive power are constant.

Therefore,

P = σεA₁T₁⁴   ----------- equation 1

where,

A₁ = Surface Area of Bulb 1

T₁ = Temperature of Bulb 1 = 3000 k

<u>FOR BULB 2:</u>

Since, emissivity and emissive power are constant.

Therefore,

P = σεA₂T₂⁴   ----------- equation 2

where,

A₂ = Surface Area of Bulb 2

T₂ = Temperature of Bulb 1 = 2000 k

Dividing equation 1 by equation 2, we get:

P/P = σεA₁T₁⁴/σεA₂T₂⁴

1 = A₁(3000)²/A₂(2000)²

A₁/A₂ = (2000)²/(3000)²

<u>A₁/A₂ = 0.44</u>

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3 years ago
Two loudspeakers are about 10 m apart in the front of a large classroom. if either speaker plays a pure tone at a single frequen
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AB and BA name the same ray
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False. Ray AB starts at point A and continues through and infinity beyond point B. Ray BA is the reverse. in the name of a Ray the starting point always comes first.
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Suppose that you toss a rock upward so that it rises and then falls back to the earth. If the acceleration due to gravity is 9.8
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"The rock has a downward acceleration of 9.8 m/s2" is the one among the following choices that explains the <span>rock’s acceleration at the instant that it reaches the top of its trajectory (where its velocity is momentarily zero). The correct option among all the options that are given in the question is option "D". </span>
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Observer 1 rides in a car and drops a ball from rest straight downward, relative to the interior of the car. The car moves horiz
steposvetlana [31]

a) 10.5 m/s

While for observer 1, in motion with the car, the ball falls down straight vertically, according to observer 2, which is at rest, the ball is also moving with a horizontal speed of:

v_x = 3.80 m/s

As the ball falls down, it also gains speed along the vertical direction (due to the effect of gravity). The vertical speed is given by

v_y = u_y + gt

where

u_y =0 is the initial vertical speed

g = 9.8 m/s^2 is the acceleration of gravity

t is the time

Therefore, after t = 1.00 s, the vertical speed is

v_y = 0 + (9.8)(1.00)=9.8 m/s

And so the speed of the ball, as observed by observer 2 at rest, is given by the resultant of the horizontal and vertical speed:

v=\sqrt{v_x^2 +v_y^2}=\sqrt{(3.8)^2+(9.8)^2}=10.5 m/s

b) \theta = -68.8^{\circ}

As we discussed in previous part, according to observer 2 the ball is travelling both horizontally and vertically.

The direction of travel of the ball, according to observer 2, is given by

\theta = tan^{-1} (\frac{v_y}{v_x})=tan^{-1} (\frac{-9.8}{3.8})=-68.8^{\circ}

We have to understand in which direction is this angle measured. In fact, the car is moving forward, so v_x has forward direction (we can say it is positive if we take forward as positive direction).

Also, the ball is moving downward, so v_y is negative (assuming upward is the positive direction). This means that the direction of the ball is forward-downward, so the angle above is measured as angle below the positive horizontal direction:

\theta = -68.8^{\circ}

4 0
3 years ago
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