Answer:
25 m/s
Explanation:
from the question you van see that some detail is missing, however i found this same question using internet search engines on: 'https://www.chegg.com/homework-help/questions-and-answers/light-rail-passenger-trains-provide-transportation-within-cities-speed-slow-nearly-constan-q5808369'
here is the complete question:
'Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant (and quite modest) acceleration. A train travels through a congested part of town at 7.0m/s . Once free of this area, it speeds up to 12m/s in 8.0 s. At the edge of town, the driver again accelerates, with the same acceleration, for another 16 s to reach a higher cruising speed. What is the final Speed?'
SOLUTION
initial speed (u) = 7 m/s
final speed (v) = 13 m/s
initial acceleration time (t1) = 8 s
final acceleration time (t2) = 16 s
what is the higher cruising speed?
acceleration = 
acceleration =  = 0.75 m/s^{2}
 = 0.75 m/s^{2}
since the train accelerates at the same rate, the increase in  speed will be = acceleration x time (t2)
= 0.75 x 16 = 12 m/s
therefore the higher cruising speed = increase in speed + initial speed
= 12 + 13 = 25 m/s
 
        
             
        
        
        
Capacitance is a measure of charge stored per volt.
        
                    
             
        
        
        
The answer is B, because it will lose potential energy.
        
             
        
        
        
Answer:
The charge on the third object is − 21.7nC 
Explanation:
From Gauss's Law
Φ = Q/ε₀
where;
Φ is the total electric flux through the shell = − 533 N⋅m²/C
Q is the total charge Q in the shell = ?
ε₀ is the permittivity of free space = 8.85 x 10⁻¹²
From this equation; Φ = Q/ε₀
Q = Φ * ε₀ = − 533 * 8.85 x 10⁻¹²
Q =  −4.7 X 10⁻⁹ C = -4.7nC
Q = q₁ + q₂ + q₃
− 4.7nC = − 14.0 nC + 31.0 nC + q₃
 − 4.7nC − 17nC = q₃ 
− 21.7nC = q₃
Therefore, the charge on the third object is − 21.7nC 
 
        
             
        
        
        
Average speed of the car is 11 m/s
Explanation:
- Speed is calculated by the rate of change of displacement. 
- It is given by the formula, Speed = Distance/Time
- Here, distance = 2155 m and time = 195.9 s
Speed of the car = 2155/195.9 = 11 m/s