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lisabon 2012 [21]
3 years ago
5

Guitar string has an overall length of 1.22 m and a total mass of 3.5 g before being strung on a guitar. Once it is used on the

guitar, there is a distance of 70 cm between fixed end points. The guitar string is tightened to a tension of 255 N.
What is the frequency of the fundamental wave on the guitar string?
Physics
1 answer:
ikadub [295]3 years ago
6 0

Answer:

Fundamental frequency= 174.5 hz

Explanation:

We know

fundamental frequency=\frac{velocity}{2 *length}

velocity =\sqrt{\frac{tension}{mass per unit length} }

mass per unit length=\frac{3.5}{1000*1.22}=0.00427\frac{kg}{m}

Now calculating velocity v=\sqrt{\frac{255}{0.00427} }

                                           =244.3\frac{m}{sec}

Distance between two nodes is 0.7 m.

Plugging these values into to calculate frequency

f = \frac{244.3}{2 *0.7} =174.5 hz

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If you doubled the load resistor in a Wheatstone bridge, the load current would not be half as much. Why not?
Fofino [41]
Doubling the size of a load resistor increases the load current. Increasing the load resistance, in turn the total circuit resistance is reduced. The load current would not be half as much since when you increase the size of load resistor then load current increases.
6 0
2 years ago
1. A hydraulic lift is to be used to lift a truck masses 5000 kg. If the diameter of the
zheka24 [161]

Answer:

a)   F = 4.9 10⁴ N,  b)   F₁ = 122.5 N

Explanation:

To solve this problem we use that the pressure is transmitted throughout the entire fluid, being the same for the same height

1) pressure is defined by the relation

           P = F / A

to lift the weight of the truck the force of the piston must be equal to the weight of the truck

          ∑F = 0

          F-W = 0

          F = W = mg

          F = 5000 9.8

          F = 4.9 10⁴ N

the area of ​​the pisto is

          A = pi r²

          A = pi d² / 4

          A = pi 1 ^ 2/4

          A = 0.7854 m²

pressure is

          P = 4.9 104 / 0.7854

          P = 3.85 104 Pa

2) Let's find a point with the same height on the two pistons, the pressure is the same

          \frac{F_1}{A_1} = \frac{F_2}{A_2}

where subscript 1 is for the small piston and subscript 2 is for the large piston

          F₁ = \frac{A_1}{A_2} \ F_2

the force applied must be equal to the weight of the truck

          F₁ = ( \frac{d_1}{d_2} )^2\  m g

          F₁ = (0.05 / 1) ² 5000 9.8

          F₁ = 122.5 N

7 0
2 years ago
The Earth's electric field creates a potential that increases 100 V for every meter of altitude. If an object of charge 4.5 mC a
castortr0y [4]

Answer:

The final kinetic energy is  K =  1.1 \ J

Explanation:

From the question we are told that

    The electric field is  E =  100 \ V/m

    The charge on the object is  q =  4.5 mC  =  4.5 *10^{-3} \ C

    The mass of the object is  m_o  =  68 \ g  = 0.68 \ kg

     The distance moved by the object is d =  1.0 \ m

The workdone on the object by the fields  is  mathematically represented as

   W =  [qE + mg]d

Now this workdone is equivalent to the final kinetic energy so  

      K = W =  [qE + mg]d

substituting values

        K = W =  [4.5*10^{-3  } *100  + 0.68 * 9.8]* 1

        K =  1.1 \ J

8 0
2 years ago
Officials begin to release water from a full man-made lake at a rate that would empty the lake in 4 weeks, but a river that can
iris [78.8K]

Answer:

5 weeks and 5 days is required to empty the lake

Explanation:

Officials begin the remove water from a full man made lake

The lake can be emptied in 4 weeks

= -1/4

A river can fill the lake up in 15 weeks

= 1/15

Let t represent the number of weeks that is required to empty the lake

= -1/t

Therefore the number of weeks it takes to empty the lake can be calculated as follows

-1/t= -1/4 + 1/15

-1/t= -11/60

Cross multiply

-11×t= -1×60

-11t= -60

t = 60/11

t= 5 5/11

Hence it takes 5 weeks and 5 days to empty the lake

6 0
3 years ago
A restaurant records the number of tables served each night, and the results have the values: minimum = 3, lower quartile = 14,
dybincka [34]

To choose the correct box plot, verify each of the options and make sure all the values in the plot match the values provided.

<h3>How to identify the median?</h3>

In a box plot, this value is represented by a vertical line located in the middle of the graph.

<h3>How to identify the maximum and the minimum?</h3>

The maximum is the value located on the farthest right, while the minimum is located on the farthest left.

<h3>How to identify the quartiles?</h3>

Divide the graph into 4 and analyze how much each quartile represents.

Learn more about graphs in: brainly.com/question/16608196

#SPJ1

5 0
2 years ago
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