Answer:
the magnitude of the magnetic force on the wire is 0.2298 N
Explanation:
Given the data in the question;
we know that, the magnitude of magnetic force is given as;
|F
| = I(
×
)
given that
I = 2.6 A
= 0.17
= 0.52
so we substitute
|F
| = 2.6( 0.17i" × 0.52j" )
|F
| = 0.2298 N
Therefore, the magnitude of the magnetic force on the wire is 0.2298 N
The common<span> feature is that the atoms of </span>all elements<span> consist of electrons, protons, and neutrons. Hope this helps!</span>
Find the intensity of the electromagnetic wave described in each case.
(a) an electromagnetic wave with a wavelength of 645 nm and a peak electric field magnitude of 8.5 V/m.
(b) an electromagnetic wave with an angular frequency of 6.3 ✕ 1018 rad/s and a peak magnetic field magnitude of 10−10 T.
It makes no sense how you typed this problem out.