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Ilia_Sergeevich [38]
2 years ago
13

Which one is the correct choice?

Mathematics
2 answers:
larisa86 [58]2 years ago
8 0

Answer:

there's no picture to look at the choices

Step-by-step explanation:

sorry I would help

VARVARA [1.3K]2 years ago
5 0
I don’t know man u should provide the choices also pls give me brainliest luv u
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PLEASE HELP quickly ​
sergejj [24]

Answer:

C. Radius or diameter must be known.

Step-by-step explanation:

The radius or diameter must be known so you can use the formula.

Hope this helps!

4 0
1 year ago
Can someone please explain the math on this one to me? Thanks!
kodGreya [7K]

Answer:

18 men = 36 tons in 6 hours

Step-by-step explanation:

3 men = 1 ton in 1 hour

6 men = 2 ton in 1 hour

9 men = 3 tons in 1 hour

with this you find a pattern

3 men = 2 tons in 2 hours

3 men = 3 tons in 3 hours

3 men = 6 tons in 6 hours

6 men = 12 tons in 6 hours

9 men = 18 tons in 6 hours

12 men = 24 tons in 6 hours

15 men = 30 tons in 6 hours

18 men = 36 tons in 6 hours

(This is how i worked it out)

8 0
3 years ago
Read 2 more answers
I need help again, as quickly as possible.
mestny [16]

Answer:

{ \tt{ \frac{1}{x}  +  \frac{1}{3}  <  \frac{1}{5} }} \\  \\ { \tt{ \frac{1}{x}   >   -  \frac{2}{15} }} \\  \\ { \tt{x >   - \frac{15}{2} }} \\  \\ { \bf{ -  \frac{15}{2} < x < 0 }}

5 0
2 years ago
Yoshi's employer pays 80% of the total cost of his family's health insurance pla, while Yodhi pays tje rest. If the total cost o
alex41 [277]

Yoshi will have to pay $50 more dollars each month.

5 0
3 years ago
Read 2 more answers
From first principles, find the indicated derivatives​
LenaWriter [7]

By definition of the derivative,

\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\left(\frac{(s + h)^3}2 + 1\right) - \left(\frac{s^3}2 + 1\right)}{h}

\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\left(\frac{s^3+3s^2h+3sh^2+h^3}2 + 1\right) - \left(\frac{s^3}2 + 1\right)}{h}

\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\frac{3s^2h+3sh^2+h^3}2}{h}

\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac12 \frac{3s^2h+3sh^2+h^3}{h}

\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac12 (3s^2+3sh+h^2)

\displaystyle\frac{dr}{ds} = \frac{3s^2}2

6 0
2 years ago
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