The rate charged per hour by each mechanic was: x = 75 $ / hr and y = 115 $ / hr.
<h3>What is a system of equations?</h3>
A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.
Given;
The first mechanic worked for 20 hours, and the second mechanic worked for 15 hours.
Together they charged a total of $3225.
For this case we have the following variables:
x be the amount of $ / hr that the mechanic obtains 1.
y be the amount of $ / hr obtained by mechanic 2.
An equation to express this would be:
x + y = 190
20x + 15y = 3225
Solving the system of equations we have:
20x + 15(190 -x) = 3225
20x + 2850 - 15x = 3225
5x = 375
x = 75
simililary
y = 190 - x
y = 115
Hence, the rate charged per hour by each mechanic was:
x = 75 $ / hr
y = 115 $ / hr
Learn more about equations here;
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Answer:
#2
Both functions have the same slope.
#3
The origin is the y-intercept for the function expressed in the table.
#5
The table and the graph express an equivalent function.
Answer:
fourth option
Step-by-step explanation:
Given f(x) then f(x + a) represents a horizontal translation of f(x)
• If a > 0 then a shift left of a units
• If a < 0 then a shift right of a units
Thus
f(x) = (x - 11)³ ← has been translated right by 11 units
Given f(x) then f(x) + c represents a vertical translation of f(x)
• If c > 0 then a shift up of c units
• If c < 0 then a shift down of c units
Thus
f(x) = (x - 11)³ + 4
represents a translation 11 units right and 4 units up
I’m pretty sure the answer is b :)
Answer:
1,778
Step-by-step explanation:
Let C and S represent the cost and salvage value of Truck B, respectively. Let X represent the number of miles per year that answers the question.
Truck A's cost for 10 years is ...
A = C+600 +(0.06)(2.25)(10X) -(S+200)
Truck B's cost for 10 years is ...
B = C +(0.07)(2.25)(10X) -S
We want to find X such that Truck A's cost is lower, so ...
C -S +1.35X +400 < C -S +1.575X
400 < 0.225X
1777 7/9 < X
1778 miles driven per year (or more) makes Truck A a better option.
