Explanation:
(a) It is known that relation between charge and volume is as follows.
=
=
=
Now, according to Gauss's law
=
= 3.68
Hence, the electric flux through this cubical surface if its edge length is 4.00 cm is 3.68 .
(b) Similarly, we will calculate the electric flux when edge length is 16.8 cm as follows.
=
=
=
Now, according to Gauss's law
=
= 2.72
Therefore, the electric flux through this cubical surface if its edge length is 4.00 cm is 2.72 .
<span>Describe the action of protein carrier: ATP synthase? Explain why it is important to have build up of Hydrogen ions inside the thylakoid?
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Answer:
0.2m
The solution is in the picture
Answer:
22.5J
Explanation:
Here the force is given. Also, the displacement is given as 30cm.
First we should check if all the values are in their standard form.
Here 30cm should be converted to metre by dividing it with 100.
Which would give us 0.3m
Now we use the equation W=force x displacement =75 x 0.3=22.5J
I hope this satisfies you. If u have any further questions please let me know.
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Answer:
correct answers C
Explanation:
the electric field is derived from Coulomb's law, where the charge has been assumed to be positive.
The expression remains
F = k q₁ q / r²
the electric field is
Fe = (k q₁ / r²) q
The amount between parentises rs constant
by checking the correct answers C