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victus00 [196]
3 years ago
8

How do professional bicycle riders reduce friction. Name two ways. Thx

Physics
1 answer:
wlad13 [49]3 years ago
4 0
A well maintained bicycle is key.  Oil the chain so that it's less likely to get hung up.  It will have a smoother flow.  Another could be in their clothing.  Notice they usually wear good fitting clothing?  I believe the more from fitting pants help clothing friction.  Another way could be keeping the tires well inflated so that the tires aren't dragging.  Rolling along smoothly on properly inflated tires seems like a must.  Get a few more answers along with mine, so that you have a variety to choose from.
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Define limitations in the operation conditions of a pn junction<br>​
suter [353]

Answer:

Such limitations are given below.

Explanation:

  • Each pn junction provides limited measurements of maximum forwarding current, highest possible inversion voltage as well as the maximum output level.
  • If controlled within certain adsorption conditions, the pn junction could very well offer satisfying performance.
  • In connector operation, the maximum inversion voltage seems to be of significant importance.

6 0
3 years ago
Calculate the net force on the right charge due to the other two. Enter a positive value if the force is directed to the right a
lbvjy [14]

Answer:

Answer:

A. - 0.017N. It acts to the left.

B. - 0.043N. It acts to the left.

C. 0.060N. It acts to the right.

Explanation:

A. For the +65μC charge, we consider it to be the origin. Hence, the two other charges are on the +x axis.

The net coulombs force on the charge is

F = [KQ(1)Q(2)]/(r^2) + [KQ(1)Q(3)]/(r^2)

Where K = Coloumbs constant =

Q(1) = charge on the leftmost side.

Q(2) = charge in the middle.

Q(3) = charge on the rightmost side.

F = [(8.988 × 10^9)×(65×10^-6)×(48×10^-6)]/(40^2) + [(8.988 × 10^9)×(-95×10^-6)×(65×10^-6)]/(40^2)

F = 0.01753 - 0.03469

F = -0.017N

It has a negative sign, hence, it acts to the left.

B. For the +48μC charge, we consider it to be the origin. Hence, the leftmost charge is on the - x axis and the rightmost charge is on the +x axis.

The net coulombs force on the charge is

F = [-KQ(1)Q(3)]/(r^2) + [KQ(2)Q(3)]/(r^2)

F = [-(8.988×10^9)×(65×10^-6)×(48×10^-6)]/(40^2) + [(8.988 × 10^9)×(48×10^-6)×(-95×10^-6)]/(40^2)

F = -0.017 - 0.02562

F = - 0.043N

It has a negative sign, hence, it acts to the left.

C. For the -95μC charge, we consider it to be the origin. Hence, the two other charges are on the - x axis.

The net coulombs force on the charge is

F = [-KQ(1)Q(3)]/(r^2) - [KQ(2)Q(3)]/(r^2)

F = [-(8.988×10^9)×(65×10^-6)×(-95×10^-6)]/(40^2) - [(8.988 × 10^9)×(48×10^-6)×(-95×10^-6)]/(40^2)

F = +0.03469 + 0.02562

F = +0.060N

It has a positive sign, hence, it acts to the right.

Read more on Brainly.com - brainly.com/question/14592748#readmore

Explanation:

5 0
3 years ago
Help this was due yesterday...
insens350 [35]

Answer:

Concept: Periodic Trends

  1. So we have Li and we have C
  2. Li has is lower in the periodic table and as you progress from s group to p group and eventually d group, the traction and ability to attract electrons increases.
  3. Hence option D
3 0
3 years ago
Read 2 more answers
A pillow is thrown downward
lara31 [8.8K]

Answer:

Is that the question?

Explanation:

5 0
3 years ago
Read 2 more answers
Exactly one pound of bread dough is placed in a baking tin. the dough is cooked in an oven at 350 °f releasing a wonderful aroma
Sladkaya [172]
The mass of the baked loaf will be less than the original dough. In making dough for bread, we have ingredients that are liquid such as water, melted butter, food flavoring, etc. All of this liquid ingredients mixed on the dough will definitely turn into vapor. This vapor is responsible for releasing of the aroma of the freshly baked bread.
7 0
3 years ago
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