<h2>
After full 30 days John will have 15 dozen speckled eggs to sell.</h2>
Step-by-step explanation:
Total number of hens John has = 51 hens
If there are 3 more hens, then total number of hens = 51 + 3 = 54 hens
Now, one third of the hens are speckled.
⇒ 18 hens are speckled.
Now, 
of the total 18 speckled hens lay speckled eggs.
⇒ 9 hens produce speckled eggs.
Now, one hen lays one egg in a day and a half.
⇒ 9 hens lay nine eggs in a day and a half
.
⇒ 9 hens lay 180 (15 doz.) eggs in 
days
Hence, after full 30 days John will have 15 dozen speckled eggs to sell.
Answer:
7 2/3
Step-by-step explanation:
Since M=1 2/3 you would do 9 1/3 - 1 2/3= 23/3 then simplify to 7 2/3
Hello!
We 1st off, know that number of pencils = x
and that the number of pens = y
So now the Solving!:
3x + y = 10
x ≤ y
Draw the line 3x + y = 10 .[it passes by (0,10) and (-10/3,0)
Draw the line y=x [it passes by (0,0), (1,1), (2,2) etc]
Then the solution is the points with integer x and y, that belong to the segment of the line 3x +y = 10 between the x-axis and the line y=x. Those points are (1,7) , (2,4), (3, 1).
I Hope my answer has come to your Help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead! :)
Answer:
p(x)+Q(x)=(2x+3y)+(x+2)=2x+3y+x+2= 3x+3y+2
<u>3x+3y+2</u> is the right answer.
