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3 years ago

How are scientists studying the effects of space on the human body?

Physics

2 answers:

Vsevolod [243]3 years ago

6 0

Answer:

The human body affects vision and bone density in space.

Explanation:

sergey [27]3 years ago

3 0

Astronauts endure radiation, weightlessness, isolation and a number of other physical and mental stresses of spaceflight.

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A large object is to be pulled along using two ropes that are attached at the same point. The angle between the two ropes is 30°

Sedbober [7]

Explanation:

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2 years ago

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At 20 degrees Celsius, conducting wires made of different materials have the same length and the same diameter. Which wire has t

DENIUS [597]

Answer:

Aluminium

Explanation:

Aluminium has the least resistance since It has 3 free electrons per atom. Its resistivity is low compared to other metals provided in the choices (gold, nichrome, tungsten). Low resistivity of metals means a high conductance of the metal referred to.

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4 years ago

A bullet at 800 m/s horizontally hits a target that is 180m away. How far does the bullet fall before it hits the target?

ale4655 [162]

The bullet falls 0.25m

The answer is -0.25m because it is falling, therefore it is negative.
Explanation:

t = dy/vy = 180m/800m/s = 0.23 secs

dy = 1/2 gt^2 = -0.25m

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3 years ago

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In which medium does light travel faster: one with a critical angle of 27.0° or one with a critical angle of 32.0°? Explain. (Fo

Eddi Din [679]

Answer:

Among those two medium, light would travel faster in the one with a reflection angle of $32^{\circ}$ (when light enters from the air.)

Explanation:

Let $v_{1}$ denote the speed of light in the first medium. Let $v_{\text{air}}$ denote the speed of light in the air. Assume that the light entered the boundary at an angle of $\theta_{1}$ to the normal and exited with an angle of $\theta_{\text{air}}$ . By Snell's Law, the sine of $\theta_{1}\!$ and $\theta_{\text{air}}\!$ would be proportional to the speed of light in the corresponding medium. In other words:

$\displaystyle \frac{v_{1}}{v_{\text{air}}} = \frac{\sin(\theta_{1})}{\sin(\theta_{\text{air}})}$ .

When light enters a boundary at the critical angle $\theta_{c}$ , total internal reflection would happen. It would appear as if the angle of refraction is now $90^{\circ}$ . (in this case, $\theta_{\text{air}} = 90^{\circ}$ .)

Substitute this value into the Snell's Law equation:

$\begin{aligned}\frac{v_{1}}{v_{\text{air}}} &= \frac{\sin(\theta_{1})}{\sin(\theta_{\text{air}})} \\ &= \frac{\sin(\theta_{c})}{\sin(90^{\circ})} \\ &= \sin(\theta_{c})\end{aligned}$ .

Rearrange to obtain an expression for the speed of light in the first medium:

$v_{1} = v_{\text{air}} \cdot \sin(\theta_{1})$ .

The speed of light in a medium (with the speed of light slower than that in the air) would be proportional to the critical angle at the boundary between this medium and the air.

For $0 < \theta < 90^{\circ}$ , $\sin(\theta)$ is monotonically increasing with respect to $\theta$ . In other words, for $\!\theta$ in that range, the value of $\sin(\theta)\!$ increases as the value of $\theta\!$ increases.

Therefore, compared to the medium in this question with $\theta_{c} = 27^{\circ}$ , the medium with the larger critical angle $\theta_{c} = 32^{\circ}$ would have a larger $\sin(\theta_{c})$ . such that light would travel faster in that medium.