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krek1111 [17]
3 years ago
6

A bullet at 800 m/s horizontally hits a target that is 180m away. How far does the bullet fall before it hits the target?

Physics
2 answers:
Rus_ich [418]3 years ago
4 0
The bullet falls 0.25 m.
ale4655 [162]3 years ago
3 0
The bullet falls 0.25m

The answer is -0.25m because it is falling, therefore it is negative.
Explanation:

t = dy/vy = 180m/800m/s = 0.23 secs

dy = 1/2 gt^2 = -0.25m
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A graph shows how the temperature of a substance changes as energy is added steadily over time.
OlgaM077 [116]

Answer:

A flat, horizontal line  

Explanation:

A flat, horizontal line indicates a phase change.

The temperature does not increase because the added heat goes into converting one phase into another.

A is wrong. A downward-sloping line indicates that the temperature is decreasing with time.

C is wrong. An upward-sloping line indicates that the temperature is increasing with time.

8 0
3 years ago
Read 2 more answers
an object is dropped from a height of 25 meters. at what velocity will it hit the ground? a 7.0 m/s b 11 m/s c 22 m/s d 49 m/s e
kipiarov [429]
Assuming that the object starts at rest, we know the following values:

distance = 25m
acceleration = 9.81m/s^2 [down]
initial velocity = 0m/s

we want to find final velocity and we don't know the time it took, so we will use the kinematics equation without time in it:

Velocity final^2 = velocity initial^2 + 2 × acceleration × distance

Filling everythint in, we have:

Vf^2 = 0^2 + (2)(-9.81)(-25)
The reason why the values are negative is because they are going in the negative direction

Vf^2 = 490.5

Take the square root of that

Final velocity = 22.15m/s which is answer c
6 0
3 years ago
12. The diameter of a circle is 2.42m. Calculate its<br>area in proper significant figure​
Sever21 [200]

Answer:

A = 4.6 [m²]

Explanation:

The area of a circle can be calculated by means of the following equation.

A=\frac{\pi }{4} *D^{2}

where:

A = area [m²]

D = diameter = 2.42 [m]

Now replacing:

A=\frac{\pi }{4} *(2.42)^{2} \\A = 4.6 [m^{2} ]

7 0
3 years ago
A 3.30-kg block starts from rest at the top of a 30.0° incline and slides a distance of 2.10 m down the incline in 1.60 s.(a) fi
AnnZ [28]
<span>Mass of the block m = 3.3kg Angle of the slide = 30 degrees Distance the block slides s = 2.10 m Time taken to slide t = 1.6 s Initially in rest condition so initial velocity u = 0. We have an equation for distance s = (u x t) + (1/2) x (a t^2) s = (0 x t) + (1/2) x (a x (1.6) ^2) => 2.10 = (1/2) x (a x2.56) 2.56a = 4.20 => a = 1.64 So the magnitude of the Acceleration a = 1.64 m/s^2</span>
8 0
3 years ago
The amount of gravitational pull an object experiences is its<br> a mass<br> b density
nata0808 [166]

The amount of gravitational pull an object experiences is its mass

<h3>What is Weight ?</h3>

Weight can be define as gravitational pull an object. It is a product of mass and acceleration due to gravity. That is, W = mg. It is measured in Newton (N)

The amount of gravitational pull an object experiences is its mass and not  density because the weight of an object depend on its mass and acceleration due to gravity.

W = mg

where

  • W = weight
  • m = mass
  • g = acceleration due to gravity

Therefore, the amount of gravitational pull an object experiences is its mass

Learn more about Weight here: brainly.com/question/19753744

#SPJ1

7 0
2 years ago
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