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Mazyrski [523]
3 years ago
7

A3-inch candle burns down in 5 hours. How far has it burned after 8

Mathematics
1 answer:
pentagon [3]3 years ago
5 0

Answer:Assuming a 3-inch diameter, pillar candles of 3, 4 and 6 inches in height will burn for 45, 60 and 75 hours, respectively. Three-inch Party Lite pillar candles will burn 30-35 hours; 5-inch, 65 to 70 hours; and 7-inch, 90 to 95 hours. The three-wick 6-by-5-inch candles burn for more than 100 hours.

Step-by-step explanation:

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F(x)=(x+4)(x-2)(x+4)(x+4)<br><br> What is the multiple zero? Multiplicity is?
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f(x)=(x+4)(x-2)(x+4)(x+4)\\f(x)=(x+4)^3(x-2)=0\\(x+4)^3=0~|~(x-2)=0\\(x+4)(x+4)(x+4)=0~|~x=2\\x=-4,2

The multiple zero is x = -4.

The multiplicity is 2 because there are two values of x.
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Britany has a bag with 2 mint sticks, 4 jelly treats, and 14 fruit tart chews. If she eats one piece every 9 minutes, what is th
zheka24 [161]
That "9 minutes" doesn't affect the outcome!

How many pieces of candy are in the bag at the beginning?  How many of those are "fruit tart chews?"  Write a fraction involving these 2 counts.  Remember that Britany immediately eats what she draws from the bag, so the 2nd time around, there are only 19 pieces, not 20.  What is the prob. that she will pick a jelly treat on her second draw?
Because these experiments are independent, you can find the joint probability by multiplying the 2 probabilities together.  Please show your work.
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3 years ago
WILL GIVE BRAINLIEST&amp; 15 PTS.
kicyunya [14]

Answer:

The given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

Step-by-step explanation:

Consider the given fraction \frac{x^3-x^2}{x^3}

We have to reduce the fraction to the lowest terms.

Consider numerator x^3-x^2

We can take x² common from both the term,

Thus, numerator can be written as x^2(x-1)

Given expression can be rewritten as ,

\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}

We can now cancel x^2 from both numerator and denominator,

\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}

\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}

Thus, the given fraction \frac{x^3-x^2}{x^3} reduces to  \frac{x-1}{x}

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Answer:

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