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2 years ago

7

A3-inch candle burns down in 5 hours. How far has it burned after 8

1 answer:

pentagon [3]2 years ago

5 0

Answer:Assuming a 3-inch diameter, pillar candles of 3, 4 and 6 inches in height will burn for 45, 60 and 75 hours, respectively. Three-inch Party Lite pillar candles will burn 30-35 hours; 5-inch, 65 to 70 hours; and 7-inch, 90 to 95 hours. The three-wick 6-by-5-inch candles burn for more than 100 hours.

Step-by-step explanation:

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How can x-(2/3)+(5/6) be solved for x in one step? Add (2/3) to both sides. Add (5/6) to both sides. Subtract (2/3) from both si

shutvik [7]

Subtract 2/3 from both sides.

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3 years ago

Una vajilla consta de 24 platos llanos, 12 platos hondos, 12 platos pequeños y 3 fuentes. Cual sera el precio de la vajilla si l

levacccp [35]

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3 years ago

Thepotemich [5.8K]

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2 years ago

In the accompanying diagram of ABC ca is extended to D, m∠ABC = 70 and m∠BCA =50 Find m∠DAB

zvonat [6]

Answer:

<em>120 degrees</em>

Step-by-step explanation:

Find the diagram attached.

From the diagram;

Interior angles are m∠BCA and m∠ABC

Exterior angle is m∠DAB

The sum of interior angle of the triangle is equal to exterior

m∠BCA +m∠ABC =m∠DAB

Given

m∠ABC = 70

m∠BCA =50

m∠DAB = 70 + 50

m∠DAB = 120 degrees

<em>Hence the measure of m∠DAB is 120 degrees</em>

6 0

2 years ago

Verify the identity. 4 csc 2x = 2 csc2x tan x

vlada-n [284]

Step-by-step explanation:

$4csc(2x) = 2csc^2(x) tan(x)$

We start with Left hand side

We know that csc(x) = 1/ sin(x)

So csc(2x) is replaced by 1/sin(2x)

$4 \frac{1}{sin(2x)}$

Also we use identity

sin(2x) = 2 sin(x) cos(x)

$4 \frac{1}{2sin(x)cos(x)}$

4 divide by 2 is 2

Now we multiply top and bottom by sin(x) because we need tan(x) in our answer

$2\frac{1*sin(x)}{sin(x)cos(x)*sin(x)}$

$2\frac{sin(x)}{sin^2(x)cos(x)}$

$2\frac{1}{sin^2(x)} \frac{sin(x)}{cos(x)}$

We know that sinx/ cosx = tan(x)

Also 1/ sin(x)= csc(x)

so it becomes 2csc^2(x) tan(x) , Right hand side

Hence verified

6 0

2 years ago