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AveGali [126]
2 years ago
5

The nuclide cobalt-60 has 27 neutrons, 33 protons, and a nuclear mass of 59. 933820 u.

Physics
1 answer:
jok3333 [9.3K]2 years ago
8 0

From the information provided in the question, the total mass of the nucleons is 60.49218 u.

<h3>What are nucleons?</h3>

The term nucleons refers to both the  neutrons and the protons that are found in the nucleus of atoms. We have the following information;

Mass of Proton: 1. 007825 u

Mass of Neutron: 1. 008665 u

Mass of 27 neutrons = 27(1. 008665 u) = 27.233955

Mass of 33 protons = 33(1. 007825 u) = 33.258225

Total mass of nucleons = 27.233955 + 33.258225 = 60.49218 u

Learn more about nucleons: brainly.com/question/9662870

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An alpha particle (the nucleus of a helium atom) consists of two protons and two neutrons, and has a mass of 6.64 * 10-27 kg. A
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t = 4.21x10⁻⁷ s

Explanation:

The time (t) can be found using the angular velocity (ω):

\omega = \frac{\theta}{t}

<em>Where θ: is the angular displacement = π (since it moves halfway through a complete circle)</em>

We have:

t = \frac{\theta}{\omega} = \frac{\theta}{v/r}  

<u>Where</u>:      

<em>v: is the tangential speed </em>

<em>r: is the radius</em>

The radius can be found equaling the magnetic force with the centripetal force:

qvB = \frac{mv^{2}}{r} \rightarrow r = \frac{mv}{qB}

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q: is the charge of the alpha particle = 2*p (proton) = 2*1.6x10⁻¹⁹C

B: is the magnetic field = 0.155 T

Hence, the time is:

t = \frac{\theta*r}{v} = \frac{\theta}{v}*\frac{mv}{qB} = \frac{\theta m}{qB} = \frac{\pi * 6.64 \cdot 10^{-27} kg}{2*1.6 \cdot 10^{-19} C*0.155 T} = 4.21 \cdot 10^{-7} s

Therefore, the time that takes for an alpha particle to move halfway through a complete circle is 4.21x10⁻⁷ s.

I hope it helps you!    

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