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Anika [276]
2 years ago
10

If two balls have the same volume,

Physics
1 answer:
Lena [83]2 years ago
8 0

Here, we are required to find the relationship between balls of different mass(a measure of weight) and different volumes.

  • 1. Ball A will have the greater density
  • 2. Ball C and Ball D have the same density.
  • 3. Ball Q will have the greater density.
  • 4. Ball X and Y will have the same density

The density of an object is given as its mass per unit volume of the object.

Mathematically;.

  • Density = Mass/Volume.

For Case 1:

  • Va = Vb and Ma = 2Mb
  • D(b) = (Mb)/(Vb) and D(a) = 2(Mb)/Vb
  • Therefore, the density of ball A,
  • D(a) = 2D(b).
  • Therefore, ball A has the greater density.

For Case 2:

  • Vc = 3Vd,

  • Vd = (1/3)Vc

  • Md = (1/3)Mc

  • D(c) = (Mc)/(Vc) and D(d) = (1/3)Md/(1/3)Vd

  • D(c) = D(d).

  • Therefore, ball C and D have the same density

For Case 3:

  • Vp = 2Vq and Mp = Mq
  • D(p) = (Mq)/2(Vq) and D(q) = (Mq)/Vq
  • Therefore, the density of ball P is half the density of ball Q
  • Therefore, ball Q has the greater density.

For case 4:

  • Mx = (1/2)My
  • Vx = Vy

Therefore, Ball X and Ball Y have the same density.

Read more:

brainly.com/question/18110802

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One uniform ladder of mass 30 kg and 10 m long rests against a frictionless vertical wall and makes an angle of 60o with the flo
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   μ = 0.37

Explanation:

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           W₁  x/2 + W₂ x₂ - fr y = 0

where W₁ is the weight of the mass ladder m₁ = 30kg, W₂ is the weight of the man 700 N, let's use trigonometry to find the distances

             cos 60 = x / L

where L is the length of the ladder

              x = L cos 60

            sin 60 = y / L

           y = L sin60

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            cos 60 = x2 / 7.0

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we substitute

         m₁ g L cos 60/2 + W₂ 7 cos 60 - fr L sin60 = 0

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let's calculate

         fr = (30 9.8 10 cos 60 2 + 700 7 cos 60) / (10 sin 60)

         fr = (735 + 2450) / 8.66

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the friction force has the expression

         fr = μ N

write the translational equilibrium equation

         N - W₁ -W₂ = 0

         N = m₁ g + W₂

         N = 30 9.8 + 700

         N = 994 N

we clear the friction force from the eucacion

        μ = fr / N

        μ = 367.78 / 994

        μ = 0.37

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Answer:

answer should be C.) Independent variable since its the one being changed

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