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3 years ago

Pls HELP I'LL MARK BRAINLEST

Mathematics

2 answers:

Vesnalui [34]3 years ago

6 0

Angles of a triangle add up to 180 degrees and then we take away the right angle
180-90=90
5x+5x=10x
90/10=9
x=9

coldgirl [10]3 years ago

6 0

The answer is d or 10

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480 stickers on 6 sheets or 120 stickers on 2 sheets? Which is the greater.

nlexa [21]

480 stickers on 6 sheets is greater because 480 divided by 6 is 80, whole 120 divided by 2 is 60

7 0

3 years ago

A=8, b=5, C=90 degree; Find c, A, and B This is for the law of sine and cosine

brilliants [131]

Answer:

• c = √89 ≈ 9.434

• A = arcsin(8/√89) ≈ 57.995°

• B = arcsin(5/√89) ≈ 32.005°

Step-by-step explanation:

By the law of cosines, ...

c² = a² + b² -2ab·cos(C)

Since c=90°, cos(C) = 0 and this reduces to the Pythagorean theorem for this right triangle.

c = √(8² +5²) = √89 ≈ 9.434

Then by the law of sines (or the definition of the sine of an angle), ...

sin(A) = a/c·sin(C) = a/c = 8/√89

A = arcsin(8/√89) ≈ 57.995°

sin(B) = b/c·sin(C) = b/c = 5/√89

B = arcsin(5/√89) ≈ 32.005°

6 0

3 years ago

Find the area of the following rhombus: 6 cm 10 cm 8 cm

alexira [117]

Answer:

480

Step-by-step explanation:

10*6=60

60*8=480

If my math is correct. I am sorry if I am wrong

8 0

3 years ago

[30 POINTS] Please help!!!

Len [333]

Answer:

Part 1) $y=1.5x+5$

Part 2) $y=-(2/3)x-(11/3)$

Part 3) $y=0.25x+2.75$

Part 4) $y=-2x+5$

Part 5) $y=0.5x-1$

Part 6) The graph in the attached figure

Step-by-step explanation:

Part 1) we have

$m=3/2=1.5$

$point(-2,2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-2=1.5(x+2)$

$y=1.5x+3+2$

$y=1.5x+5$

Part 2) we know that

If two lines are perpendicular

then

the product of their slopes is equal to minus one

$m1*m2=-1$

the slope of the line 1 is equal to

$m1=1.5$

Find the slope m2

$1.5*m2=-1$

$m2=-2/3$

Find the equation of the line 2

we have

$m2=-2/3$

$point(-7,1)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-1=(-2/3)(x+7)$

$y=-(2/3)x-(14/3)+1$

$y=-(2/3)x-(11/3)$

Part 3) we have

$m=1/4=0.25$

$point(1,3)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-3=0.25(x-1)$

$y=0.25x-0.25+3$

$y=0.25x+2.75$

Part 4) we have

$m=-2$

$b=5$ -----> y-intercept

we know that

The equation of the line into slope intercept form is equal to

$y=mx+b$

substitute the values

$y=-2x+5$

Part 5) we have that

The slope of the line 4 is equal to $-2$

the slope of the line perpendicular to the line 4 is equal to

$-2*m=-1\\m=(1/2)=0.5$

therefore

in this problem we have

$m=0.5$

$point(-2,-2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y+2=0.5(x+2)$

$y=0.5x+1-2$

$y=0.5x-1$

Part 6)

using a graphing tool

see the attached figure

3 0

3 years ago

The sum of three consecutive odd integers is 195. Find the three integers.

Anettt [7]

Good afternoon,

x= first odd integer
x+2 = second odd integer
x+4= third intenger

The sum of the trhree integer is 195, so:

x + (x+2) + (x+4) = 195
3x = 195 - 4 - 2
3x=189
x= 63

Then the Answer is: 63, 65 and 67

8 0

3 years ago

Read 2 more answers