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Furkat [3]
2 years ago
14

[30 POINTS] Please help!!!

Mathematics
1 answer:
Len [333]2 years ago
3 0

Answer:

Part 1) y=1.5x+5  

Part 2) y=-(2/3)x-(11/3)

Part 3) y=0.25x+2.75    

Part 4) y=-2x+5  

Part 5) y=0.5x-1  

Part 6) The graph in the attached figure

Step-by-step explanation:

Part 1) we have

m=3/2=1.5

point(-2,2)

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

substitute

y-2=1.5(x+2)

y=1.5x+3+2

y=1.5x+5

Part 2) we know that  

If two lines are perpendicular

then

the product of their slopes is equal to minus one

so

m1*m2=-1

the slope of the line 1 is equal to

m1=1.5

Find the slope m2

1.5*m2=-1

m2=-2/3

Find the equation of the line 2  

we have

m2=-2/3

point(-7,1)

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

substitute

y-1=(-2/3)(x+7)

y=-(2/3)x-(14/3)+1

y=-(2/3)x-(11/3)

Part 3) we have

m=1/4=0.25

point(1,3)  

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

substitute

y-3=0.25(x-1)

y=0.25x-0.25+3

y=0.25x+2.75

Part 4) we have

m=-2

b=5 -----> y-intercept

we know that

The equation of the line into slope intercept form is equal to

y=mx+b

substitute the values

y=-2x+5

Part 5) we have that

The slope of the line 4 is equal to -2

so

the slope of the line perpendicular to the line 4 is equal to

-2*m=-1\\m=(1/2)=0.5

therefore

in this problem we have

m=0.5

point(-2,-2)

The equation of the line into point slope form is equal to

y-y1=m(x-x1)

substitute

y+2=0.5(x+2)

y=0.5x+1-2

y=0.5x-1

Part 6)

using a graphing tool

see the attached figure

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