A. Alright, we want to multiply one equation by a constant to make it cancel out with the second. Since the first equation has a "blank" y, let's multiply the first equation by <em>2</em>.

3x-y=0 → 2(3x-y=0) = 6x - 2y = 0

5x+2y=22

The answer for this part would be: 6x - 2y = 0 and 5x + 2y = 22

B. So now we combine them:

6x - 2y = 0

+ + +

5x + 2y = 22

= = =

11x + 0 = 22 ← The answer

C. Now that we have the equation 11x = 22, we solve for x

11x = 22 ← Divide both sides by 11

x = 2 ← The answer

D. Now that we have x=2, we plug that back in to 5x+2y=22 and solve for y:

5(2)+2y = 22

10 + 2y = 22

2y = 12

y = 6

<u>Therefore, the solution to this problem is x = 2 and y = 6</u>

5 0

3 years ago

Last year, Ravi opened an investment account with $5400 . At the end of the year, the amount in the account had decreased by 24.

Nastasia [14]

1-(24.5/100)=0.755 which will be our multiplier
5400 x 0.755 = $4077 left in his account
5400-4077=$1323 decrease

3 0

3 years ago