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gladu [14]
3 years ago
11

M=2*2*3*5*5 and N=2*2*2*3*3*7 find the largest number that divides exactly M and N​

Mathematics
1 answer:
Gelneren [198K]3 years ago
6 0

Answer:

6

Step-by-step explanation:

M=2*2*3*5*5=300

N=2*2*2*3*3*7=504

Common factors between the two numbers are 2 and 3

The GCF(greatest common factor):

2×3 = 6

To see if it is true:

300/6 = 50

504/6 = 84

6 is the answer to the question.

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Which expression is equivalent to (c-2d) times (3c-2d)?
timama [110]

Answer:

B

Step-by-step explanation:

(c - 2d) (3c - 2d) =  c*(3c -2d) - 2d(3c - 2d)

6 0
3 years ago
I don’t understand this and I did take notes on this on the computer but I still don’t understand it.
Serggg [28]

Answer:

<em>I</em>'[−3, −2], <em>Q</em>'[2, 0], <em>?</em>'[0, 1], <em>E</em>'[−3, −1]

Step-by-step explanation:

The line of reflection is at <em>y = −</em><em>2</em>,<em> </em>so looking at the line and where the coordinates of the shape are, you will have this:

<em>I</em>[−3, −2] → <em>I</em>'[−3, −2] (on the line, so it remains the same)

<em>Q</em>[2, −4] → <em>Q</em>'[2, 0]

<em>?</em>[0, −5] →<em> </em><em>?</em>'[0, 1]

<em>E</em>[−3, −3] → <em>E</em>'[−3, −1]

I am joyous to assist you anytime.

3 0
3 years ago
Give the position of c on this number line write a fraction for your number​
alex41 [277]

Answer:

2/6 or 1/3

Step-by-step explanation:

<em>It izz wat it izzzz!!!</em>

8 0
3 years ago
Read 2 more answers
A dairy company gets milk from two dairies and then blends the milk to get the desired amount of butterfat. Milk from dairy I co
zubka84 [21]

Answer:

a) i The company should buy 40 gallons from dairy I and 60 gallons from dairy

ii) What is the maximum amount of​ butterfat? The total amount of butterfat from Diary I and Diary II = 3.12% + 1.93%

=5.05%

b.The excess capacity of dairy I is 10 ​gallons, and for dairy II it is 30 gallons.

Step-by-step explanation:

a. How much milk from each supplier should the company buy to get at most 100 gallons of milk with the maximum amount of​ butterfat?

From the question, we are told that:

Milk from dairy I costs ​$2.40 per​ gallon, Milk from dairy II costs ​$0.80 per gallon.

Let's represent:

Number of gallons of Milk from dairy I = x

Number of gallons of Milk from dairy II = y

At most ​$144 is available for purchasing milk.

$2.40 × x + $0.80 × y = 144

2.40x + 0.80y = 144........ Equation 1

x + y = 100....... Equation 2

x = 100 - y

2.40(100 - y) + 0.80y = 144

240 - 2.4y + 0.80y = 144

-1.60y = 144 - 240

-1.6y = -96

y = -96/-1.6

y = 60

From Equation 2

x + y = 100....... Equation 2

x + 60 = 100

x = 100 - 60

x = 40

Therefore, since number of gallons of Milk from dairy I = x and number of gallons of Milk from dairy II = y

The company should buy 40 gallons from dairy I and 60 gallons from dairy

II. What is the maximum amount of​ butterfat?

From the question

Dairy I can supply at most 50 gallons averaging 3.9​% ​butterfat,

50 gallons = 3.9% butterfat

40 gallons =

Cross Multiply

= 40 × 3.9/50

= 3.12%

Dairy II can supply at most 90 gallons averaging 2.9​% butterfat.

90 gallons of milk = 2.9% butter fat

60 gallons of milk =

Cross Multiply

= 60 × 2.9%/90

=1.9333333333%

≈ 1.93%

The total amount of butterfat from Diary I and Diary II = 3.12% + 1.93%

=5.05%

b. The solution from part a leaves both dairy I and dairy II with excess capacity. Calculate the amount of additional milk each dairy could produce.

Excess capacity of Diary I =

50 gallons - 40 gallons = 10 gallons

Excess capacity of Diary II =

90 gallons - 60 gallons = 30 gallons

Therefore, the excess capacity of dairy I is 10 ​gallons, and for dairy II it is 30 gallons.

3 0
3 years ago
Assume that the random variable X is normally distributed with mean u = 45 and standard deviation o = 14.
larisa86 [58]

Answer:

P(57 < X < 69) = 0.1513

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 45, \sigma = 14

Find P(57 < X < 69):

This is the pvalue of Z when X = 69 subtracted by the pvalue of Z when X = 57. So

X = 69

Z = \frac{X - \mu}{\sigma}

Z = \frac{69 - 45}{14}

Z = 1.71

Z = 1.71 has a pvalue of 0.9564

X = 57

Z = \frac{X - \mu}{\sigma}

Z = \frac{57 - 45}{14}

Z = 0.86

Z = 0.86 has a pvalue of 0.8051

0.9564 - 0.8051 = 0.1513

P(57 < X < 69) = 0.1513

4 0
3 years ago
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