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castortr0y [4]
2 years ago
10

Calcular P (k) para la distribución binomial B (n, p) donde: (a) n = 5, p =, k = 2 (b) n = 10, p = k = 7 (c) n = 8, p =. k = 5.​

Mathematics
1 answer:
Vladimir [108]2 years ago
3 0

Answer:

Step-by-step explanation:

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Write the point-slope form of the line that passes through (5, 5) and is PARALLEL to a line with a slope of 1/4. Include all of
lesya692 [45]
Parallel lines will have the same slope

y - y1 = m(x - 1)
slope(m) = 1/4
(5,5)...x1 = 5 and y1 = 5
now we sub
y - 5 = 1/4(x - 5) <==== ur parallel line
==================
perpendiculr lines will have a negative reciprocal slope. To find the negative reciprocal, u flip the number and change the sign. So the negative reciprocal of 1/4 is -4....see how I flipped 1/4 and made it 4/1...then changed the sign making it -4/1 or just -4. That will be ur slope of the perpendicular line.

y - y1 = m(x - x1)
slope(m) = -4
(5,5)...x1 = 5 and y1 = 5
now we sub
y - 5 = -4(x - 5) <=== ur perpendicular line
4 0
3 years ago
Calculate the number of ways that the coach can assign the 4 positions to his 16 players.
Natali5045456 [20]

The number of ways that the coach can assign the 4 positions to his 16 players would be 43, 680 ways

<h3>How to calculate the permutation</h3>

The formula for permutation is given as;

Permutation = \frac{n!}{(n - r)!}

n = 16

r =4

Permutation = \frac{16!}{12!}

Permutation = \frac{16 *15*14*13*12*11*10*9*8*7*6*5*4*3*2*1}{12*11*10*9*8*7*6*5*4*3*2*1}

Permutation = 43, 680 ways

Thus, the number of ways that the coach can assign the 4 positions to his 16 players would be 43, 680 ways

Learn more about permutation here:

brainly.com/question/12468032

#SPJ1

8 0
2 years ago
**IF ANYONE CAN DO ALL OF THESE QUESTIONS CORRECTLY AND FAST, YOU WILK BE MARKED BRAINLIEST!!**What is the measure of arc BC?
bixtya [17]

I think the answer is BC= (bc + de)/2

7 0
3 years ago
If bill has 300 dresses with a weight of 30 pounds each. How do you find the average weight of all of the dresses with the volum
maria [59]
The answer is 9000 hope this helps
3 0
3 years ago
Toni can carry up to 18 lb in her backpack. Her lunch weighs 1 lb, her gym clothes weigh 2 lb, and her books (b) weigh 3 lb each
MrRissso [65]
<span>Toni can carry five books in her backpack. You must start by subtracting the weight of the other required items. Toni's lunch which is one pound and gym clothes which are two pounds. This can be calculated by 18-1-2=15. Toni has 15 pounds left to carry books. She should divide this by the weight of each book, which is three pounds. 15/3=5. Therefore, Toni can carry five books.</span>
3 0
3 years ago
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