2sin²(-2490)+tan 1410=2sin²(-330-6*360)+tan (330+3*360)=
=2sin²(-330)+tan (330)=2 sin²(30-1*360)+tan (-30)=
=2sin²(30)-tan (30)=2(1/2)²-√3/3=1/2-√3/3)=(3-2√3)/6
Answer: 2 sin²(-2490)+tan (1410)=(3-2√3)/6 (≈-0.07735...)
Answer:
d=1.4
Step-by-step explanation:
cuz 10-1.4=8.6
2x^2 +3x -4 +8 -3x -5x^2 +2
-3x^2 + 6
Answer is C) -3x^2 + 6
