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Rom4ik [11]
3 years ago
12

HELp mEEEEEEE pLssssssss

Mathematics
2 answers:
EastWind [94]3 years ago
8 0

Answer:

its #3

Step-by-step explanation:

hope this helps

Marrrta [24]3 years ago
8 0

it's 3

Step-by-step explanation:

Hope it is correct

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Express 60 as the product of its prime factors in ascending order and give your answer in index form
Allisa [31]

Answer:

{2}^{2}, 3, 5 are the prime factors of 60.

Step-by-step explanation:

60 = 2 \times 2 \times 3 \times 5 \\  =  {2}^{2}  \times 3 \times 5 \\

3 0
3 years ago
Heeeeeelp! I’m literally so behind
olchik [2.2K]

Answer:

That would be 9 my good sir ( or ma'am )

Step-by-step explanation:

basicly round the 61 so that there would not be a remainder and divide 54 by 6 you will get 9, so therefore the same case is for 540 by 60.

Have a nice day

7 0
2 years ago
Complete the square to rewrite x^2+y^2+2x+6y-6=0 in graphing form
Ksivusya [100]

Answer:

(x + 1)² + (y + 3)² = 16

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Given

x² + y² + 2x + 6y - 6 = 0

Collect the x and y terms together and add 6 to both sides

x² + 2x + y² + 6y = 6

To complete the square

add ( half the coefficient of the x/ y terms )² to both sides

x² + 2(1)x + 1 + y² + 2(3)y + 9 = 6 + 1 + 9

(x + 1)² + (y + 3)² = 16

with centre = (- 1, - 3) and r = \sqrt{16} = 4

4 0
3 years ago
Which is a factor of 144 − 49x2?<br><br> 12 - 7x2<br> 72 – 7x2<br> 12 – 7x<br> 72 + 7x
Vinil7 [7]

Answer:

(12-7x)

Step-by-step explanation:

144 − 49x²

by observation, we can see that 144 = 12² and 49 = 7²

hence we can rewrite the equation

144 − 49x²

= 12² - 7²x²

= 12² - (7x)²

recall that the expression x² - y² = (x+y)(x-y)

hence,

12² - (7x)²

= (12 + 7x)(12-7x)

(12-7x) appears in the expression above, hence 12 -7x is a factor

5 0
3 years ago
Read 2 more answers
The blue dot is at what value on the number line?
viva [34]

Answer:

-5

Step-by-step explanation:

5 0
3 years ago
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