3,000 is 10 times as much as
3000 = 10 times of what number
We need to find 10 times what number gives us 3000
Let the unknown number be x
3000 = 10 times x
3000 = 10x
To solve for x, we divide by 10 on both sides

300 = x
So, the unknown number is 300
3000 = 10 times 300
3000 is 10 times as much as 300
The equation for point-slope form is <span>y - y1 = m(x - x1)
</span>
Answer:
16192
Step-by-step explanation:
The Least Common Multiple (LCM) of the numbers
88,92,64
is
16192
<span>The <u>correct answer</u> is:
Extrapolation, because a key that is 12 keys from middle c is outside the data set.
Explanation<span>:
<u>Interpolation </u>is inserting an <u>intermediate value into an existing series</u> using estimation or calculations from nearby values. A key 12 keys from middle C is not in the data set involved, so this is not interpolation.
<u>Extrapolation </u>involves using a trend or pattern to <u>estimate unknown values past the values we have</u>. Since this key would be past our data set that we have, this would be extrapolation.</span></span>
<h3>16 lollipops and 9 bags of chips are sold</h3>
<em><u>Solution:</u></em>
Let "x" be the number of lollipops sold
Let "y" be the number of bags of chips sold
Cost of 1 lollipop = $ 1.50
Cost of 1 bag of chip = $ 1.75
<em><u>Yesterday Lucy made $39.75 from selling a total of 25 lollipops and bags of chips</u></em>
Therefore,
x + y = 25
y = 25 - x -------- eqn 1
<em><u>Yesterday Lucy made $39.75</u></em>
Therefore,
number of lollipops sold x Cost of 1 lollipop + number of bags of chips sold x Cost of 1 bag of chip = 39.75

1.5x + 1.75y = 39.75 -------- eqn 2
<em><u>Substitute eqn 1 in eqn 2</u></em>
1.5x + 1.75(25 - x) = 39.75
1.5x + 43.75 - 1.75x = 39.75
0.25x = 4
<h3>x = 16</h3>
<em><u>Substitute x = 16 in eqn 1</u></em>
y = 25 - 16
<h3>y = 9</h3>
Thus 16 lollipops and 9 bags of chips are sold