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2 years ago

5

A pool cleaning service drained a full pool. The table shows the number of hours it drained and and the amount of water remainin

g in the pool at that time. I need help pleaseeee help me

2 answers:

FinnZ [79.3K]2 years ago

8 0

Answer:

I can help but for a price.

Step-by-step explanation:

Ilia_Sergeevich [38]2 years ago

6 0

B
C
B

im so sorry if im wrong

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Which is greater 8/10 or 80/100

balandron [24]

They are equal because of you simplify 80/100 by dividing by 10 u get 8/10

6 0

2 years ago

Read 2 more answers

Without calculating the answer for 5 1/5 * 2/5 be larger or smaller than 5 1/5

solniwko [45]

Answer:

Evidently, without the calculating 5 1/5 times 2/5 would be larger than 5 1/5 since you are already gonna multiply 2/5 and that would make it larger.

Hope this helps!

Branliest would be appreciated :DD

Step-by-step explanation:

4 0

2 years ago

A map distance of 5 inches represents 200 miles of actual distance . Suppose the distance between two cities on the map is 7 inc

Naily [24]

$\frac{5}{200} = \frac{7}{x} \\ 5x = 1400 \\ x = 280$

therefore, the actual distance is 280 miles.

(sorry, idk the rule for it)

7 0

2 years ago

Read 2 more answers

...............................

antoniya [11.8K]

Answer:

<h2> $2 \sqrt{10}$ </h2>

Option C is the correct option.

Step-by-step explanation:

√ 8 • √ 5

Calculate the product

$= \sqrt{40}$

Simplify the radical expression

$= \sqrt{2 \times 2 \times 10}$

$= 2 \sqrt{10}$

Hope this helps...

Best regards!!

4 0

2 years ago

Please solve the problem

jek_recluse [69]

Treat the matrices on the right side of each equation like you would a constant.

Let 2<em>X</em> + <em>Y</em> = <em>A</em> and 3<em>X</em> - 4<em>Y</em> = <em>B</em>.

Then you can eliminate <em>Y</em> by taking the sum

4<em>A</em> + <em>B</em> = 4 (2<em>X</em> + <em>Y</em>) + (3<em>X</em> - 4<em>Y</em>) = 11<em>X</em>

==> <em>X</em> = (4<em>A</em> + <em>B</em>)/11

Similarly, you can eliminate <em>X</em> by using

-3<em>A</em> + 2<em>B</em> = -3 (2<em>X</em> + <em>Y</em>) + 2 (3<em>X</em> - 4<em>Y</em>) = -11<em>Y</em>

==> <em>Y</em> = (3<em>A</em> - 2<em>B</em>)/11

It follows that

$X=\dfrac4{11}\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\dfrac1{11}\begin{bmatrix}7&-10\\-7&11\end{bmatrix} \\\\ X=\dfrac1{11}\left(4\begin{bmatrix}12&-3\\10&22\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\left(\begin{bmatrix}48&-12\\40&88\end{bmatrix}+\begin{bmatrix}7&-10\\-7&11\end{bmatrix}\right) \\\\ X=\dfrac1{11}\begin{bmatrix}55&-22\\33&99\end{bmatrix} \\\\ X=\begin{bmatrix}5&-2\\3&9\end{bmatrix}$

Similarly, you would find

$Y=\begin{bmatrix}2&1\\4&4\end{bmatrix}$

You can solve the second system in the same fashion. You would end up with

$P=\begin{bmatrix}2&-3\\0&1\end{bmatrix} \text{ and } Q=\begin{bmatrix}1&2\\3&-1\end{bmatrix}$

3 0

2 years ago