A line passes through the two points (-4,6) and (2,-5). 11x +6y - 80 = 0 is the given line equation.
<h3>What is the slope of a line which passes through points ( p,q) and (x,y)?</h3>
Its slope would be:
The slope of parallel lines are same. Slopes of perpendicular lines are negative reciprocal of each other.
The slope m of the line is given as
The equation of a line is
Hence, the equation is 11x +6y - 80 = 0
Learn more about slopes here:
brainly.com/question/2503591
#SPJ4
Answer: A=20.8, B=20.5, C=10, D=2, E=12.6
Explanation: It takes time, but all you have to do it make an equation adding all the sides together, which equals 85.9. Then find “a” and plug that back in to each side. (I’m pretty sure this is right, but sorry if I’m wrong)
Answer:
25
Step-by-step explanation:
Let n be the first integer.
Then the second integer will be (n + 1).
And the third will be (n + 2).
The sum is 78. Therefore:
Solve for n. Combine like terms:
So:
Therefore:
Therefore, the first integer is 25.
So our sequene is 25, 26, and 27.
The integer closest to zero will thus be 25.
∠DBC = 19° since the two angles have to add up to 180, if x = 23, then 23 -4 = 19 for the right, and 7 x 23 = 161, and 161 + 19 = 180.
