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Murrr4er [49]
3 years ago
6

A boat pulls an inner tube behind it using a rope. The rope exerts a force 155 N on the inner tube at an angle of 5.88 above the

horizontal. What are the horizontal and vertical components of this force?

Physics
1 answer:
mylen [45]3 years ago
7 0

Answer:

154 N horizontal (to the right) 15.9 N vertical (up)

Explanation:

I got it right :)

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An alpha particle travels at a velocity of magnitude 520 m/s through a uniform magnetic field of magnitude 0.034 T. (An alpha pa
Keith_Richards [23]

Answer:

(a) Magnetic force F=38.584\times 10^{-19}N

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(a) Force acting on the particle is equal to

F=q(v\times B)=qvBsin\Theta

F=3.2\times 10^{-19}\times 320\times 0.034\times sin43^{\circ}

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(B) According to newton's law

F = ma. here m is mass and a is acceleration.

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(c) As the magnetic force is always perpendicular to velocity so speed will remain same neither decreases nor increases.

4 0
3 years ago
For each combination, record the total force, total mass, and acceleration. On the last column, multiply the mass (m) and accele
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Hello. You did not present the combinations the question refers to, which makes it impossible for this question to be answered accurately. However, I will try to help you in the best possible way.

To present the total force you must use the following formula: Mass x Acceleration.

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