Answer: 5289 joules
Explanation:
The quantity of Heat Energy (Q) required to heat a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)
Thus, Q = MCΦ
Since, Mass of ice = 20 g
C is not provided (Recall that the specific heat capacity of ice is 2.010J/g°C)
Φ = (Final temperature - Initial temperature)
(120°C - (-25°C) =
120°C + 25°C = 145°C
Thus, Q = 20g x 2.010J/g°C x 145°C
Q= 5829J
Thus, 5829Joules of heat energy is required to heat ice
This should help
there always needs to be the two electrons first if possible the 8 electrons for each shell till the number of electron runout
I'd say a weekly news magazine.
True, when charging a secondary cell, energy can be stored within a dielectric material using an electric field.
<h3>Relationship between dielectric material and electric field</h3>
The electric field in a capacitor separates the negative and positive charges in the dielectric material, this causes an attractive force between each plate and the dielectric.
The dielectric material can store electric energy due to its polarization in the presence of external electric field, which causes the positive charge to store on one electrode and negative charge on the other.
Thus, when charging a secondary cell, energy can be stored within a dielectric material using an electric field.
Learn more about dielectric material here: brainly.com/question/17090590
