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11Alexandr11 [23.1K]
3 years ago
8

Technician A says a respirator will block all poisonous fumes produced in a shop. Technician B says a respirator will block only

those fumes for which it is rated. Who is right?
Physics
1 answer:
dem82 [27]3 years ago
6 0

Answer:

Technician B

Explanation:

There's no such thing as a perfect filter available to block any kind of toxic fumes. The effectiveness of a filter depends of various things, such as the air flow and the particles size. They have specific rates depending on the place they are designed to be installed on, so they have to be chosen with that in mind. For example, most industrial applications have more demanding restrinctions than a commercial one, so a filter designed for the latter would probably not be useful for the first case.

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  • <em><u>Option B) reactive to nonreactive</u></em>

Explanation:

<u>A) Solid to gas</u>

This might apply, because most of the gases are to the right portion of the periodic table

There are just a few elements that are gases at room temperature; a total of 11: six noble gases (group 18), two halogens (group 17), oxygen (group 16), nitrogen (group 15), and hydrogen (group 1).

Hydrogen is an exception to this trend because they are in the left part of the periodic table.

<u>B) Reactive to nonreactive</u>

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Hence, this is the one that cannot apply.

<u>C) Metal to metalloid to nonmetal</u>

It is true that the metallic character of the elements decreases from left to right; the metals are to the left, going to the right you find some metalloids, and further to the right you find the nonmetals.

Hence, this trend is correct.

<u />

<u>D) Increasing number of outer-shell electrons</u>

The number of outer-shell electrons definetly increase from left to right.

The number of electrons in neutral atoms equals the number of protons (to balance the positive and negative charges). Since, the atomic number (the number of protons) increase from left to right, the number of electrons also increase.

In a period (a row of the periodic table) the electrons add to the same outer-shell, then you will find that the number of electrons of the outer-shell increase from left to right. Hence, this is also a correct trend.

In conclusion, the only trend that does not apply is the described by the option B).

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