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larisa [96]
2 years ago
10

PLEASE HELP ASAPExplain how can a ripple tank be used to view wave pattern.

Physics
1 answer:
Ivan2 years ago
7 0

Answer:

when you push up and down the pencil right in the middle of the water tank. it will produce ripples. If seen at the perfect angle you will observe the waves

Explanation:

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A box is being pulled by two ropes. Eduardo pulls to the left with a force of 500 N, and Clara pulls to the right with a force o
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Answer:

kinetic friction or something else

Explanation:

Draw a diagram to illustrate the problem, as shown below.

m = mass of the box, kg

mg =  weight of the box, N, acting downward

Because of Newton's 3rd law, a normal force of N = mg acts upward on the box.

C = 200 N, the force applied by Clara, horizontally to the right

E = 500 N, the force applied by Eduardo, horizontally to the left.

Because E is greater than C, the box will move left.

The frictional force, F, will resist the initial motion. Its magnitude is

F = μN = μmg, where μ = kinetic coefficient of friction.

F acts horizontally to the right.

From the given table, we can conclude that

Normal force acting upward is correct

Tension by Eduardoacting left is correct.

Tension by Clara acting right is correct.

Kinetic friction acting left is Incorrect.

Gravity acting downward is correct.correct

Answer:

The direction of the kinetic friction force is incorrect

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3 years ago
Suppose Car 1 collides with Car 2; Car 2 was not moving. In an ideal situation with no friction, according to the Law of Conserv
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Your answer is C it is slightly reduced
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Read 2 more answers
A 6.7 kg block is released from rest on a frictionless inclined plane making an angle of 25.7° with the horizontal. Calculate th
yulyashka [42]

Answer:

So time taken by block to travel 0.5 m from rest will be 0.4853 sec

Explanation:

We have given mass of the block m = 6.7 kg

angle of inclination \Theta =25.7^{\circ}

Distance traveled s = 0.5 m

Initial velocity u = 0 m/sec

Acceleration of the block a=gsin\Theta =9.8\times sin25.7^{\circ}=4.243m/sec^2

From second equation of motion we know that S=ut+\frac{1}{2}at^2

So 0.5=0\times t+\frac{1}{2}\times 4.243\times t^2

t^2=0.2356

t = 0.4853 sec

So time taken by block to travel 0.5 m from rest will be 0.4853 sec

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3 years ago
Astronomers think most galaxy interactions took place at redshifts of greater than 1 because
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Because they are moving away from us.
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