Answer:
72%
Step-by-step explanation:
you can divide part of a whole by the whole to get a decimal
this decimal is the percentage when you move the decimal 2 places to the right
32 - 9 = 23 men
23/32 = .72 (rounded)
.72 = 72%
Answer:
0.5122 or 51.22%
Step-by-step explanation:
In a certain city, in June Probability of cloudy days = P(cloudy) = 0.41
Probability of cloudy and rainy = P(cloudy and rainy) = 0.21
Probability of rainy if we already know it is cloudy = ![\frac{\text{[P(cloud and rainy)]}}{[P(cloud)]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7B%5BP%28cloud%20and%20rainy%29%5D%7D%7D%7B%5BP%28cloud%29%5D%7D)
=
= 0.512195122 ≈ 0.5122
Therefore, the probability that a randomly selected day in June will be rainy if it is cloudy is 0.5122 or 51.22%
If UT is the midsegment of QRS, then SQ = 2(2x + 2) = 4x + 4
Then,
(3x + 1)/(7x - 1) = (2x + 2)/(4x + 4) = 1/2
2(3x + 1) = 7x - 1
6x + 2 = 7x - 1
7x - 6x = 2 + 1
x = 3
Therefore, SQ = 4(3) + 4 = 12 + 4 = 16.
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