<span> 110y+10=340
Subtract 10 from both sides
110y=330
Divide by 110 to get variable on its own
</span>110y/110=330/110
y=3
Step-by-step explanation:
Radius (r) = 2 ft
V = 4/3 × 22/7 × (2)³
= 4/3 × 22/7 × 8
= 33.52 ft³
Step-by-step explanation:
<h3><u>G</u><u>i</u><u>v</u><u>e</u><u>n</u><u> </u><u>Inform</u><u>ation</u><u> </u><u>:</u></h3>
- Ryan spent 1/3 of his monthly salary for rent and 1/7 of his monthly salary for his utility bill.
- Remaining money = $759
<h3><u>T</u><u>o</u><u> </u><u>calculate</u><u> </u><u>:</u></h3>
<h3><u>C</u><u>a</u><u>l</u><u>c</u><u>u</u><u>l</u><u>a</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>:</u></h3>
Let us assume his monthly salary as x. According to the question,
➝ Money spent on rent + Money spent for utility bill + Remaining money = His salary








<u>Therefore,</u><u> </u><u>his</u><u> </u><u>monthly</u><u> </u><u>income</u><u> </u><u>is</u><u> </u><u>$</u><u>1</u><u>4</u><u>4</u><u>9</u><u>.</u>
Answer: 1/3
Step-by-step explanation:
Here is the complete question:
machine is set to pump cleanser into a process at the rate of 9 gallons per minute. Upon inspection, it is learned that the machine actually pumps cleanser at a rate described by the uniform distribution over the interval 8.5 to 11.5 gallons per minute. Find the probability that between 9.0 gallons and 10.0 gallons are pumped during a randomly selected minute.
The Probability of the above question will be calculated as:
= (10-9) / (11.5 - 8.5)
= 1/3
The above is the easier way to solve this