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allochka39001 [22]
3 years ago
10

Need help ...,,.....,,........

Mathematics
1 answer:
Hatshy [7]3 years ago
6 0

Answer:

i’m pretty sure that it’s 50. i haven’t done this in a awhile though. but pretty positive it’s 50

Step-by-step explanation: :)

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Define a new random variable by y = 2px. show that, as p l 0, the mgf of y converges to that of a chi squared random variable wi
Mandarinka [93]
The moment generating function (mgf) of y is given by

M_y(t)=E(e^{ty})=E(e^{2pxt})=M_x(2pt)=p(1-e^{2pt}(1-p))^{-1}

Since the momoent generating function of x is given by M_x(t)=p(1-e^{t}(1-p))^{-1}

When p tends to 0, we have

\lim_{p \to 0} M_y(t)=  \lim_{p \to 0}  \frac{p}{1-e^{2pt}(1-p)} = \frac{0}{0}

Applying L'Hopital's rule we have:

\lim_{p \to 0} M_y(t)=\lim_{p \to 0} \frac{1}{e^{2pt}+2te^{2pt}+2pte^{2pt}} = \frac{1}{1+2t} , \ \ \ t\ \textless \  \frac{1}{2}

This shows that y converges to <span>a chi squared random variable with 2r degrees of freedom</span>.
5 0
3 years ago
Paulo has won the lottery. He is offered a series of payments of $10,000 per year for 10 years. What is the present value of the
sergiy2304 [10]

The present value of the payments is $73,600.87.

Present value of a cash flow is the value of the cash flow today. This is determined by adding the discounted cash flows of the cash flows together.  

Discounted year 1 cash flow: 10,000 / (1.06) = 9,433.96

Discounted year 2 cash flow: 10,000 / (1.06)^2 = 8,899.96

Discounted year 3 cash flow: 10,000 / (1.06)^3 = 8,296.19

Discounted year 4 cash flow: 10,000 / (1.06)^4 = 7,920.94

Discounted year 5 cash flow: 10,000 / (1.06)^5 = 7,472.58

Discounted year 6 cash flow: 10,000 / (1.06)^6 = 7,049.61

Discounted year 7 cash flow: 10,000 / (1.06)^7 = 6,650.57

Discounted year 8 cash flow: 10,000 / (1.06)^8= 6,274.12

Discounted year 9 cash flow: 10,000 / (1.06)^9 = 5,918.98

Discounted year 10 cash flow: 10,000 / (1.06)^10 = 5,583.95

The sum of the discounted cash flows = $73,600.87

A similar question was solved here: brainly.com/question/9641711?referrer=searchResults

4 0
2 years ago
Draw 4 non collinear points
harina [27]
I don't know if you have to do this on a graph, or just on a blank space. But, noncollinear means, "not on the same line". So, if you were to draw four points in a blank spot on a piece of paper, just draw four points in random places, making sure they aren't all directly in line with eachother. For a graph, use points like: (-6,2), (5,7), (8,3), and (1,-3). Notice that none of them have the same x or y coordinates, so they can't possibly be collinear.
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3 years ago
What the image of (- 6, 5) after a reflection over the line y = x ?
zubka84 [21]

Answer:

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Step-by-step explanation:

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3 years ago
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Answered.                            ...........
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