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Jet001 [13]
3 years ago
6

Which statement correctly compares what occurs when molecules absorb photons in the microwave region with what occurs when molec

ules absorb photons in the infrared region?
a.) Microwave photons cause the molecules to increase their rotational energy states, whereas infrared photons cause the molecules to increase their vibrational energy states.
b.) Microwave photons cause electrons in the molecules to increase their electronic energy states, whereas infrared photons cause the molecules to increase their rotational energy states.
c.) Microwave photons cause the molecules to increase their vibrational energy states, whereas infrared photons cause electrons in the molecules to increase their electronic energy states.
d.) Microwave photons cause the molecules to increase their rotational energy states, whereas infrared photons cause electrons in the molecules to increase their electronic energy states.
Chemistry
2 answers:
Fiesta28 [93]3 years ago
6 0

Answer:

It is a.) Microwave photons cause the molecules to increase their rotational energy states, whereas infrared photons cause the molecules to increase their vibrational energy states.

Explanation:

you are increasing the vibrational energy states

ValentinkaMS [17]3 years ago
5 0

Answer:

d.) Microwave photons cause the molecules to increase their rotational energy states, whereas infrared photons cause electrons in the molecules to increase their electronic energy states.

Explanation:

Microwave: transitions in the molecular rotational levels

Infrared: transitions in molecular vibrational levels

UV/Visible: transitions in electronic energy levels.

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Shkiper50 [21]
It was named the Qumran seas scrolls.
3 0
3 years ago
A solution contains 72.0 g of HCI and 468 g of (C6H6). what is the mole fraction of benzene
erica [24]
<span>Molar mass (MM) of benzene C6H6
C = 6 * 12 = 72u
H = 6 * 1 = 6u
MM C6H6 = 72 + 6 = 78 g / mol
Benzene - Molar Mass = 78 g --------- 1 mol
Of A Mix has 468 g -------------- x

78x = 468
X = 468/78
X = 6 moles
 
Molar mass (MM) of Hydrochloric Acid HCl H = 1 * 1 = 1u
CI = 1 * 35 = 35u
MM HCl = 1 + 35 = 36 g / mol
 
Hydrochloric Acid - Molar Mass = 36 g ---------- 1 mol
Of A Mix has 72 g ------------ y

36y = 72
Y = 72/36
Y = 2 moles
 
Thus, a mixture has a total of 8 moles (6 mol + 2 mol).
Dividing One Mole Amount of Each Substance by the Number of Total Mole Amounts, Then we will obtain a Molar Fraction of Each:
Molar fraction make benzene = (6/8) simplify 2 = 3/4
Molar Fraction to make Hydrochloric Acid = (2/8) = simplify 2 = 1/4

Note:. The sum of the molar fractions of the always give goes 1, we have: 3/4 + 1/4 = 1
 

ANSWER: 
</span>\boxed{\frac{3}{4}}
4 0
3 years ago
Identify the outer electron configurations for the (a) alkali metals, (b) alkaline earth metals, (c) halogens, (d) noble gases.
Doss [256]
a) Alkali metals

=> group 1

=> Li:  1s2 2s  => 1s
     Na: [Ne] 3s => 3s
     K: [Ar] 4s => 4s
     Rb: [Kr] 5s => 5s
     Cs: [Xe] 6s => 6s
     Fr: [Rn] 7s => 7s

=> outer electron configuration is ns, where n is the main energy level: 1, 2, 3, 4, 5, 6,7.
     
b) Alkaline earth metals

=> group 2 => you have to add 1 electron to the alkaly metal of the same row.

=> Be: [He] 2s2 => 2s2
     Mg: [Ne] 3s2 => 3s2
     Ca: [Ar] 4s2 => 4s2
     Sr: [Kr] 5s2 => 5s2
     Ba: [Xe] 6s2 => 6s2
     Ra: [Rn[ 7s2 => 7s2

=>outer electron configuration is n s2, where n is the main energy level: 1, 2, 3, 4, 5, 6, 7

c) halogens

=> group 7

=> F: [He] 2s2 2p5 => 2s2 2p5
     Cl: [Ne] 3s2 3p5 => 3s2 3p5
     Br: [Ar] 3d10 4s2 4p5 => 4s2 4p5
     I: [Kr] 4d10 5s2 5p6 => 5s2 5p5
     At: [Xe] 4f14 5d10 6s2 6p5

=> outer electron configuration is ns2 np5, where n is the main energy level 1, 2, 3, 4, 5, 6, 7

d) Noble gases

=> group 8

I will show only the outer shell which is what is requested

=> He: 1s2
     Ne: ... 2s2 2p6
     Ar: ... 3s2 3p6
     Kr: ... 4s2 4p6
     Xe: ... 5s2 5p6
     Rn: ... 6s2 6p6

=> the outer electron configuration is ns2 np6, except for He for which it is 1s2
6 0
4 years ago
If 110g of copper sulphate is present in 550g of solution calculate the concentration of solution
Bingel [31]

Answer:

20%

Explanation:

mass by mass percentage of a solution =(mass of solute)/(mass of solution)

mass of solute=550g

therefore 110×100/550=20%

hope u will understand .:") credit to the owner

7 0
3 years ago
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Leno4ka [110]
Ba(OH)2 is an basic solution. It has more OH- ions than H+ ions. pOH should be calculated to find out its pH
The reaction is
Ba(OH)2 ⇒ Ba2+ (aq) + 2 OH-(aq)
One mole barium hydroxide releases 2 moles hydroxide ions.

Use that ratio to calculate molarity (M) of OH- ions [OH-]. The ratio is 1:2. 
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[OH-]= 0.02
pOH= - log [OH-] = - log 0.02 = 1.7
Thats not the answer! We found pOH of the solution before titration.
pH and pOH relationship is shown by formula of pH+pOH= 14 
pH= 14-pOH
pH= 14-1.7= 12.3

7 0
4 years ago
Read 2 more answers
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