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Alex_Xolod [135]
3 years ago
9

A student calculated the molarity of a solution prepared by dissolving 0.730 mol of table sugar (sucrose, C12H22O11) in 1.8x10^3

mL of water as 4.06x10^-4 M C12H22O11. Explain the student's calculation error and explain how the student should solve for the correct value of molarity. Show a valid calculation for the molarity.
Chemistry
1 answer:
kenny6666 [7]3 years ago
8 0

The student made a mistake because he did not convert a unit of volume from milliliters to liters. After all, molarity is defined as the number of moles of solute per liter of solution.

Answer: C=0.406M.C=0.406M.

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goldenfox [79]
I'd say it would be
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3 years ago
C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(l)
stiv31 [10]

¹/3 C3H8(g) + ⁵/3 O2(g)

Explanation:

The coefficient before every molecule is representative of the number of moles. We can represent it in ration form so as to calculate the question;

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(l) means;

For every 1 mole of C₃H₈(g) and 5 moles of  O₂(g) produces  3 moles of  CO₂(g) and 4 moles of H₂O(l).

Therefore to produce 1.00 mole of CO₂(g);

We represent it in ratio;

C₃H₈(g) : CO₂(g)

1  :     3

What about ;

? (x)   :  1

We cross multiply;

3x = 1 * 1

X = 1/3

We evaluate the same for O₂;

O₂(g) : CO₂(g)

5 :     3

What about

? (x) :     1

3x = 5 * 1

x = 5/3

Learn More:

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7 0
2 years ago
How many moles of oxygen are consumed in the complete combustion of 1.60 moles of benzene, c6h6?
My name is Ann [436]

In the complete combustion of 1.60 moles of benzene, C6H6, 12 moles of oxygen, O2, is consumed.

Combustion is defined as the process of burning something. In chemistry, combustion refers to the chemical process between a fuel and an oxidant, usually oxygen to produce heat and light in the form of flame.

In a complete combustion, oxygen is sufficient to react with any hydrocarbons to produce carbon dioxide and water.

Balancing the combustion reaction of benzene, we have:

2C6H6 + 15 O2 = 12CO2 + 6H2O

Based on the balanced combustion reaction above, 2 moles of benzene requires 15 moles of oxygen to have a complete combustion.

If we have 1.60 moles C6H6,

moles O2 = mole ratio x mole of benzene

moles O2 = (15 moles O2/2 moles C6H6) x 1.60 moles C6H6

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3 0
2 years ago
Are you friend with Nitrogen and Oxygen
Oduvanchick [21]

Nitrogen and oxygen do not react at ambient temperature. At high temperatures they have endothermic reactions and produces various oxides of nitrogen.

Explanation:

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The atoms combines with one another to form molecules. The nitrogen is a inert, colorless gas with no smell or taste, its harmless to human beings.

The oxygen and nitrogen are abundant gases in the atmosphere and have similar physical properties. The oxygen (O2) is twice as soluble in water as nitrogen (N2).

8 0
2 years ago
Why is oil unable to dissolve well in water? Water is polar and oil is nonpolar, which means they have no attraction for each ot
Marat540 [252]
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3 0
3 years ago
Read 2 more answers
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