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Karolina [17]
3 years ago
14

Jasper works as an inspector at a factory that makes polo shirts. He has found that the probability of a shirt that is produced

being defective is . If 1,350 polo shirts are produced in one day at the factory, which of the following is the best prediction of the number of defective polo shirts?
Mathematics
1 answer:
jasenka [17]3 years ago
8 0

It's b cause ur bad and beautiful naw i,m just playin all u gotta do is use a calculator no duh it's that easy    

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Erin found 9 cents<br> each day for 7 days.<br> How much money did<br> she find in all?
kherson [118]
After 7 days she would have eventually found 63 cents.
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Read 2 more answers
The length if Sally's garden is 4 meters greater than 3 times the width. The perimeter of her garden is 72 meters. Find the dime
ololo11 [35]

Answer: So lets say that the width is w. The length(L) is 4 meters greater than 3 times the width. 3 times the width would be 3w, and then 4 meters greater than that would be 3w+4. You have two widths and two lengths to a rectangle that must add up to equal 72. So 2w + 2L =72. But remember that one L equals 3w+4

2(w) + 2(3w+4) = 72

2w+6w+8=72

8w+8=72

8w=64

w=8

L=3w+4

L=3(8)+4

L=24+4

L=28

So the dimensions are 8 meters by 28 meters

To check 2(8)+2(28)=72

6 0
4 years ago
I neeed helpppppppppppppppp
Stolb23 [73]

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ Jeff will earn $267.20 in a 32 hour week.

Divide to find how much he gets paid per hour:

$334 ÷ 40 = $8.35

Multiply the cost per hour by 32 hrs to get the total amount he'll get paid:

$8.35 × 32 = $267.20

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

5 0
3 years ago
In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel
Lady bird [3.3K]

Answer:

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

Now,

change in sulfur oxide with time i.e \frac{\textup{dS}}{\textup{dt}}

differentiating the given relation with respect to time 't'

we have

2S\frac{\textup{dS}}{\textup{dt}} =  2\times110P\frac{\textup{dP}}{\textup{dt}}  + 20

at P = 100 and  \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

we have

2S\frac{\textup{dS}}{\textup{dt}} = 2 × 110 × 100 × 10 + 20

or

2S\frac{\textup{dS}}{\textup{dt}} = 220020

or

\frac{\textup{dS}}{\textup{dt}} = \frac{\textup{220020}}{\textup{2S}}

or

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

8 0
3 years ago
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