Answer:
a) P(X∩Y) = 0.2
b) 
= 0.16
c) P = 0.47
Step-by-step explanation:
Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.
So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67
Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:
P(X∩Y) = P(X) + P(Y) - P(X∪Y)
P(X∩Y) = 0.36 + 0.51 - 0.67
P(X∩Y) = 0.2
On the other hand, the probability that he must stop at the first signal but not at the second one can be calculated as:
= P(X) - P(X∩Y)
= 0.36 - 0.2 = 0.16
At the same way, the probability 
that he must stop at the second signal but not at the first one can be calculated as:
= P(Y) - P(X∩Y)
= 0.51 - 0.2 = 0.31
So, the probability that he must stop at exactly one signal is:
Answer:
9x+15
Step-by-step explanation:
Answer:
a.)1/3
Step-by-step explanation:
Answer:
-1/5
Step-by-step explanation:
slope formula:
m = y₂ - y₁ / x₂ - x₁
Two points are given:
(-5, -5) (5, -7)
m = -7 - (-5) / 5 - (-5)
m = -2 / 10
m = -1/5
Answer:
A) 0 and 13
Step-by-step explanation:
64 - 37 = 27
27/2 = 13.5
13 teachers can teach 3 classes at max
