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s344n2d4d5 [400]
2 years ago
15

-0)

Mathematics
1 answer:
Sphinxa [80]2 years ago
5 0
30 because 25% minese 10
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A Norman window has the shape of a semicircle atop a rectangle so that the diameter of the semicircle is equal to the width of t
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Answer:

132.233 ft2

Step-by-step explanation:

Let's call the width of the rectangle 'w' and the length 'x'. So the area of the semicircle is:

A_1 = \pi*radius^2/2

A_1 = \pi*(w/2)^2/2

A_1 = \pi/8*w^2

And the area of the rectangle is:

A_2 = w*x

If the perimeter of the window is 41 feet, we have:

Perimeter = length + 2*width + \pi*radius

41 = x + 2*w + \pi*w/2

x = 41 - w(2 + \pi/2)

Now, the equation for the total area of the window is:

A = A_1 + A_2 = \pi/8*w^2 + w*x

A = \pi/8*w^2 + w*(41 - w(2 + \pi/2))

A = (\pi/8-2 - \pi/2)*w^2 + 41w = -3.1781w^2 + 41w

To find the maximum area, we can find the x-coordinate of the vertex of the quadratic equation:

x\_vertex = -b / 2a = -41 / (-3.1781*2) = 6.45

So the width that gives us the maximum area of the window is 6.45 feet, and the area will be:

A = -3.1781w^2 + 41w = -3.1781*(6.45)^2 + 41*6.45 = 132.233\ ft^2

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Anybody know this? or the guide to this??
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the length of missing side is 28

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