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velikii [3]
3 years ago
7

Figure 24-40 shows a thin rod with a uniform charge density of 2.40 μC/m. Evaluate the electric potential (in V) at point P if d

= D = L/5.00.
Physics
1 answer:
LuckyWell [14K]3 years ago
7 0
Can you send a picture???
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Phase unbalance causes three-phase motors to operate at temperatures ? and, therefore, the motor cannot deliver its rated horsep
anastassius [24]

Phase unbalance causes three-phase motors to operate at temperatures higher than nameplate ratings and, therefore, the motor cannot deliver its rated horsepower.

<h3>What is an electric vehicle (EV)?</h3>

An EV stands for an electric vehicle. Electric vehicles (EVs) are autos that are powered totally or partially by electricity.

Electric cars are extremely cost-effective to run because they have fewer moving parts to maintain and use little to no fossil fuels (petrol or diesel).

Hence, three-phase motors operating with phase imbalance run at temperatures over nameplate limits, which prevents the motor from producing its rated horsepower.

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To learn more about electric vehicles here,

brainly.com/question/27434548

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7 0
2 years ago
A 70-kg boy is sitting 3 m from the ground in a tree. What is his gravitational potential energy
steposvetlana [31]

m x h x 9.8 m/s squared

70 kg x 3 m x 9.8 m/s squared= 2058 Joules

7 0
3 years ago
Say you want to make a sling by swinging a mass M of 2.3 kg in a horizontal circle of radius 0.034 m, using a string of length 0
ycow [4]

Answer:

T = 764.41 N

Explanation:

In this case the tension of the string is determined by the centripetal force. The formula to calculate the centripetal force is given by:

F_c=m\frac{v^2}{r}  (1)

m: mass object = 2.3 kg

r: radius of the circular orbit = 0.034 m

v: tangential speed of the object

However, it is necessary to calculate the velocity v first. To find v you use the formula for the kinetic energy:

K=\frac{1}{2}mv^2

You have the value of the kinetic energy (13.0 J), then, you replace the values of K and m, and solve for v^2:

v^2=\frac{2K}{m}=\frac{2(13.0J)}{2.3kg}=11.3\frac{m^2}{s^2}

you replace this value of v in the equation (1). Also, you replace the values of r and m:

F_c=(2.3kg)(\frac{11.3m^2/s^2}{0.034})=764.41N

hence, the tension in the string must be T =  Fc = 764.41 N

5 0
3 years ago
What quantity is represented by a unit called a newton (N)?
zavuch27 [327]

\textsf {C. Force}

\textsf {The quantity which is represented by a unit called Newton (N)}\\\textsf {is Force.}

5 0
2 years ago
What if you were a mother for a day boys and girls
Dominik [7]
I’m am a mother no drama !!!!

Boom
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3 years ago
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