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AnnZ [28]
3 years ago
11

A force of 4 kg weight acts on a body of mass 9.8 kg calculate the acceleration

Physics
2 answers:
klio [65]3 years ago
4 0
  • Mass=9.8kg
  • Force=4N

Using newtons second law

\\ \bull\sf\dashrightarrow Force=Mass\times Acceleration

\\ \bull\sf\dashrightarrow Acceleration=\dfrac{Force}{Mass}

\\ \bull\sf\dashrightarrow Acceleration=\dfrac{9.8}{4}[tex][tex]\\ \bull\sf\dashrightarrow Acceleration=2.45m/s^2

White raven [17]3 years ago
3 0

Answer:

here given is a weight

then force becomes mg

that is F=Mg

=4*9.8

then by using the formula

F=Ma

a=F/M

=4*9.8/9.8

=4

Explanation:

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6 0
4 years ago
Which scientific term is defined as the rate at which work is accomplished?
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7 0
3 years ago
The sound intensity a distance d1 = 15.0 m from a chain saw is 0.260 W/m2. What is the sound intensity a distance d2 = 27.0 m fr
bagirrra123 [75]

Answer:

0.08024 W/m²

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P = Power

d_1 = Distance = 15 m

I_1 = Intensity at 15 m = 0.26 W/m²

d_2 = Distance = 27 m

I_1 = Intensity at 27 m

Sound intensity is given by

I=\frac{P}{4\pi d^2}

\\\Rightarrow I\propto \frac{1}{d^2}

So, we have the relation

\frac{I_1}{I_2}=\frac{d_2^2}{d_1^2}\\\Rightarrow I_2=\frac{d_1^2\times I_1}{d_2^2}\\\Rightarrow I_2=\frac{15^2\times 0.26}{27^2}\\\Rightarrow I_2=0.08024\ W/m^2

The sound intensity at the given distance is 0.08024 W/m²

8 0
4 years ago
The 10-kg block is held at rest on the smooth inclined plane by the stop block at A. If the 10-g bullet is traveling at 300 m/s
Nadusha1986 [10]

Answer:

d=6.874mm

Explanation:

Linear momentum of the block is conserved in the x\prime direction since the impulsive force due to impact cancels each other internally.

m_bv_b_x=(m_b+m_B)v_x\\(0.01)(300cos 30\textdegree)=(10+0.01)v\\\therefore v=0.259548m/s

Using the conservation of energy to the block system considering the initial position:

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Applying Sine rule:

d=\frac{h}{Sin 30\textdegree}\\d=6.874mm

Hence, the distance the block will slide up is 6.874mm

5 0
3 years ago
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