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AnnZ [28]
3 years ago
11

A force of 4 kg weight acts on a body of mass 9.8 kg calculate the acceleration

Physics
2 answers:
klio [65]3 years ago
4 0
  • Mass=9.8kg
  • Force=4N

Using newtons second law

\\ \bull\sf\dashrightarrow Force=Mass\times Acceleration

\\ \bull\sf\dashrightarrow Acceleration=\dfrac{Force}{Mass}

\\ \bull\sf\dashrightarrow Acceleration=\dfrac{9.8}{4}[tex][tex]\\ \bull\sf\dashrightarrow Acceleration=2.45m/s^2

White raven [17]3 years ago
3 0

Answer:

here given is a weight

then force becomes mg

that is F=Mg

=4*9.8

then by using the formula

F=Ma

a=F/M

=4*9.8/9.8

=4

Explanation:

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Explanation:

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Can a compound be broken down into simpler substances
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Review. (c) Assume the dipole is a compass needle-a light bar magnet-with a magnetic moment of magnitude μ . It has moment of in
hammer [34]

The frequency of oscillation is \frac{1}{2\pi }  \sqrt{\frac{\mu B}{I} }.

<h3>What is a magnetic moment?</h3>

The magnetic moment is the magnetism of a magnet or other item that creates a magnetic field, as well as its orientation and strength. Electromagnets, permanent magnets, elementary particles like electrons, different compounds, and a variety of celestial objects are examples of things that have magnetic moments (such as many planets, some moons, stars, etc). The phrase "magnetic moment" typically refers to a system's magnetic dipole moment, which can be represented by an analogous magnetic dipole, which has a magnetic north and south pole that are barely separated from one another. For sufficiently small magnets or at sufficiently wide distances, the magnetic dipole component is adequate. For extended objects, additional terms may be required in addition to the dipole moment, such as the magnetic quadrupole moment.

T = \frac{ Id^{2}\theta }{dt^{2} }

-\mu B\theta=\frac{ Id^{2}\theta }{dt^{2} }

\frac{d^{2}\theta }{dt^{2} } = -(\frac{\mu BI}{\theta} )

By Comparing the above equation with the SHM equation

\frac{d^2 \theta} {dt^{2} } = -\omega^{2} \theta

\omega^{2} =\frac{ \mu B}{I}

Frequency = \frac{\mu}{2\pi }

=\frac{\sqrt{\frac{\mu B}{I} } }{2\pi}

=\frac{1}{2\pi }  \sqrt{\frac{\mu B}{I} }

To learn more about a magnetic moment, visit:

brainly.com/question/17000031

#SPJ4

8 0
1 year ago
A ball rolls onto the path of your car as you drive down a quiet neighborhood street. To avoid hitting the child that runs to re
ehidna [41]

Answer:

F = 7.143 kN

Explanation:

given,

time taken to apply break = 1.05 s

car slows down from 15 m/s to 9 m/s

mass of the car = 1250 Kg

force is equal to the change in momentum with respect to time.

F = \dfrac{\Delta P}{t}

F = \dfrac{m(v_f - v_i)}{t}

F = \dfrac{1250\times (9 - 15)}{1.05}

F = \dfrac{-7500}{1.05}

F = -7142.85 N

F = - 7.143 kN

Force is acting opposite direction of velocity of car i.e. the sign is negative.

7 0
3 years ago
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