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olga55 [171]
4 years ago
14

Which statement about the horizontal distance covered by a projectile launched at an angle less than 90° is true?

Physics
2 answers:
MArishka [77]4 years ago
7 0

Answer:

A

Explanation:

mylen [45]4 years ago
5 0
<h2>Answer: A</h2>

Explanation because the distance covered is equal time intervals is the same or equal.

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A.without a long antenna, 're signal will not travel far

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The frequency and wavelength of EM waves can vary over a wide range of values. Scientists refer to the full range of frequencies
mestny [16]

Complete question is;

The frequency and wavelength of EM waves can vary over a wide range of values. Scientists refer to the full range of frequencies that EM radiation can have as the electromagnetic spectrum. Electromagnetic waves are used extensively in modern wireless technology. Many devices are built to emit and/or receive EM waves at a very specific frequency, or within a narrow band of frequencies. Here are some examples followed by their frequencies of operation:

garage door openers: 40.0 MHz

standard cordless phones: 40.0 to 50.0 MHz

baby monitors: 49.0 MHz

FM radio stations: 88.0 to 108 MHz

cell phones: 800 to 900 MHz

Global Positioning System: 1227 to 1575 MHz

microwave ovens: 2450 MHz

wireless internet technology: 2.4 to 2.6 GHz

Which of the following statements correctly describe the various applications listed above? Check all that apply.

a.) All these technologies use radio waves, including low-frequency microwaves.

b.) All these technologies use radio waves, including high-frequency microwaves.

c.) All these technologies use a combination of infrared waves and high-frequency microwaves.

d.) Microwave ovens emit in the same frequency band as some wireless Internet devices.

e.) The radiation emitted by wireless Internet devices has the shortest wavelength of all the technologies listed above.

f.) All these technologies emit waves with a wavelength in the range of 0.10 to 10.0 m.

g.) All the technologies emit waves with a wavelength in the range of 0.01 to 10.0 km.

Answer:

B, D, E, F are the correct statements.

Explanation:

Looking at the options;

A) This is true because radio waves are electromagnetic radiation being used today in television, mobile phones, radios and other areas of communication technologies. And the examples given to us fall in the category of technologies that use radio waves.

B) microwaves usually have long wavelengths and low frequencies. However, sometimes they could have high frequencies usually more than radio waves. Thus, this option is correct.

C) This option is wrong because it's not all the listed technologies that use combination of infrared waves and high-frequency microwaves.

D) we are given the frequency of microwave ovens as 2450 MHz.

Converting to GHz gives; 2.45 GHz.

We are told that wireless internet technology has frequency between 2.4 to 2.6 GHz. Thus, microwave frequency falls in the same range as wireless internet technology and thus the statement is true.

E) we know that wavelength is inversely proportional to frequency. This means that the higher the frequency, the shorter the wavelength.

In the frequencies given to us, wireless internet technology have the highest frequency which means they have the shortest wavelength. The statement is true.

F) from the frequencies given to us, the smallest is garage door openers = 40.0 MHz = 40 × 10^(6) Hz while the biggest is 2.6 GHz = 2.6 × 10^(9) Hz

Formula for wavelength is;

Wavelength = speed of light/frequency

Speed of light = 3 × 10^(8) m/s

Thus;

Wavelength = (3 × 10^(8))/(40 × 10^(6))

Or wavelength = (3 × 10^(8))/(2.6 × 10^(9))

So,wavelength = 7.5 m or 0.12 m

This falls into the given range of 0.10 to 10.0 m.

Thus, the statement is true.

8 0
3 years ago
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A single-turn circular loop of radius 14 cm is to produce a field at its center that will just cancel the earth's magnetic field
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Answer:

49 A

Explanation:

We are given that

Number of turns,N=1

Radius,r=14 cm=\frac{14}{100}=0.14 m

1 m=100 cm

Magnetic field,B=0.7 G=0.7\times 10^{-4} T

1G=10^{-4} T

\mu_0=4\pi\times 10^{-7} Tm/A

We know that magnetic field

B=\frac{\mu_0IN}{2\pi r}

Substitute the values

0.7\times 10^{-4}=\frac{4\pi\times 10^{-7}\times 1\times I}{2\pi\times 0.14}

I=\frac{0.7\times 10^{-4}\times 2\pi\times 0.14}{4\pi\times 10^{-7}\times 1}

I=49A

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