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Juli2301 [7.4K]
2 years ago
14

Express: 0.006 in exponeutialform​

Mathematics
1 answer:
Yuri [45]2 years ago
3 0

6×10^-3

Step-by-step explanation:

0.006

Move the point to the front of the first number that is from 1 to 9.

In the question it's 6, so you move it to the front of 6 .

And because it's from back to front it has to have a negative sign in its power

which is going to be

6× 10^-3

where 6=the number from 1 to 9

^ means raise to power or power of

-3= the negative power

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Which expression is equivalent to -5(m - 3)?<br> -5(-3 + m)<br> 15m - 5<br> -5(-3m)<br> -3(m - 5)
Zepler [3.9K]

Answer:

the first one

Step-by-step explanation:

The first equation is -5m+15

and the first one is 15-5m

Which is basically the same thing.

Glad to help

6 0
3 years ago
A system contains n atoms, each of which can only have zero or one quanta of energy. How many ways can you arrange r quanta of e
My name is Ann [436]

Answer:

\mathbf{a)} 2\\ \\ \mathbf{b)} 184 \; 756 \\ \\\mathbf{c)}  \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}

Step-by-step explanation:

If the system contains n atoms, we can arrange r quanta of energy in

                         \binom{n}{r} = \dfrac{n!}{r!(n-r)!}

ways.

\mathbf{a)}

In this case,

                                n  = 2, r=1.

Therefore,

                    \binom{n}{r} = \binom{2}{1} = \dfrac{2!}{1!(2-1)!} = \frac{2 \cdot 1}{1 \cdot 1} = 2

which means that we can arrange 1 quanta of energy in 2 ways.

\mathbf{b)}

In this case,

                                n  = 20, r=10.

Therefore,

                    \binom{n}{r} = \binom{20}{10} = \dfrac{20!}{10!(20-10)!} = \frac{10! \cdot 11 \cdot 12 \cdot \ldots \cdot 20}{10!10!} = \frac{11 \cdot 12 \cdot \ldots \cdot 20}{10 \cdot 9 \cdot \ldots \cdot 1} = 184 \; 756

which means that we can arrange 10 quanta of energy in 184 756 ways.

\mathbf{c)}

In this case,

                                n = 2 \times 10^{23}, r = 10^{23}.

Therefore, we obtain that the number of ways is

                    \binom{n}{r} = \binom{2\times 10^{23}}{10^{23}} = \dfrac{(2\times 10^{23})!}{(10^{23})!(2\times 10^{23} - 10^{23})!} = \dfrac{(2\times 10^{23})!}{(10^{23}!)(10^{23})!}

3 0
3 years ago
Pharmacy Technician Rolando received a prescription for 150 calcium carbonate tablets for the patient. Rolando used 1/3 of the s
Feliz [49]
450

If he used 1/3 of the stock bottle, then you have
150=1/3x

Now, you multiply both sides by 3, which gives you

450=x

So, originally there were 450 bottles in the stock bottle
7 0
3 years ago
4+8/2* (6-3). Please answerrrr
Andrew [12]

Answer:

16

Step-by-step explanation:

brainliest plss

5 0
3 years ago
Read 2 more answers
9x+63=100 please answer my question
valina [46]

Answer:

x=3

Step-by-step explanation:

9x+63=100

9x+0=27

9(3)=27

8 0
3 years ago
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