Un elev a depus la banca suma de 250 lei. Știind ca banca oferă dobânda anuala de 1%,iar stația impozitează dobânda cu 16%,aflat
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Answer:
a) Expected amount of the gambler's win = $0.209
b) SD = 2.26
c)P (X >1) = P(z >0.35) = 0.36317
Step-by-step explanation:
The probability of winning, p = 12/38 =6/19
Probability of losing, q = 1 -p = 1-6/19
q = 13/19
Win amount = $5
Loss amount = $2
a) Expected total amount of win = ((6/19)*5) - ((13/19)*2)
Expected total amount of win = 1.579 - 1.369
Expected amount of win, E(X) = $0.209
b) Standard Deviation for the total amount of the gambler's win
E(X²) = (6/19)*5² - (13/19)*2²
E(X²) = 5.158
SD = 2.26
c) probability that, in total, the gambler wins at least $1.
P(X >1)
μ = E(x) = 0.209
z = (1-0.209)/2.26
z = 0.35
P( X >1) = P(z >0.35)
P(z >0.35) = 1 - P(z <0.35)
P(z >0.35) = 1 - 0.63683
P(z >0.35) = 0.36317
Please find attached photograph for your answer.
Answer:
Step-by-step explanation:
The interquartile range is IQR is:
Where:
= third quartile
= first quartile
So the interquartile range is the difference between the highest quartile and the lowest quartile. In other words, it is the width of the box in the diagram.
So:
The R range is the difference between the highest value and the lowest. In other words:
Finally: