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Likurg_2 [28]
3 years ago
12

Can you help me with this. Is this a function, why or why not?

Mathematics
1 answer:
stellarik [79]3 years ago
3 0
Yes it is a function
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A woodworker makes 238 wooden bowls a month. At the rate, how many bowls will he make in 12 months?
d1i1m1o1n [39]

Answer:

2856

Step-by-step explanation:

if you multiply 238 by 12

you will get the ans

4 0
3 years ago
Read 2 more answers
Find the seventh term of the geometric sequence 1, 2, 4, ... and the sum of the first seven terms. t7= S7=
IrinaK [193]

Answer:

Seventh term is 64

Sum of the first seven terms is 127

Step-by-step explanation:

The common ratio is 2

a_{n}  = a_{1} r^{n - 1}    

n = 7 and the first term is 1.  So,

a_{7}  =  1(2^{7 - 1} )  = 2^{6} = 64

Seventh term is 64

S_{n}  =  \frac{a_{1} (r^{n} -1)}{r - 1}

S_{7} = \frac{1(2^{7} -1)}{2 - 1}

    = \frac{128 - 1}{1} = 127

Sum of the first seven terms is 127

8 0
3 years ago
How many terms are in this expression? 4x + 3y - 12x + 5
Vladimir79 [104]
There are 4 terms in the expression.

Terms are each of the entities.

4x,  + 3y ,  -12x,   +5
5 0
3 years ago
Find the value of x.
riadik2000 [5.3K]
We know that both lines will be equivalent, so to solve for x we can equate the two expressions
5x = 2x + 63
We will first subtract 2x from both sides
3x = 63
We will then divide both sides by 3
x = 21
7 0
3 years ago
Compute the matrix of partial derivatives of the following functions.
s344n2d4d5 [400]

For a vector-valued function

\mathbf f(\mathbf x)=\mathbf f(x_1,x_2,\ldots,x_n)=(f_1(x_1,x_2,\ldots,x_n),\ldots,f_m(x_1,x_2,\ldots,x_n))

the matrix of partial derivatives (a.k.a. the Jacobian) is the m\times n matrix in which the (i,j)-th entry is the derivative of f_i with respect to x_j:

D\mathbf f(\mathbf x)=\begin{bmatrix}\dfrac{\partial f_1}{\partial x_1}&\dfrac{\partial f_1}{\partial x_2}&\cdots&\dfrac{\partial f_1}{\partial x_n}\\\dfrac{\partial f_2}{\partial x_1}&\dfrac{\partial f_2}{\partial x_2}&\cdots&\dfrac{\partial f_2}{\partial x_n}\\\vdots&\vdots&\ddots&\vdots\\\dfrac{\partial f_m}{\partial x_1}&\dfrac{\partial f_m}{\partial x_2}&\cdots&\dfrac{\partial f_n}{\partial x_n}\end{bmatrix}

So we have

(a)

D f(x,y)=\begin{bmatrix}\dfrac{\partial(e^x)}{\partial x}&\dfrac{\partial(e^x)}{\partial y}\\\dfrac{\partial(\sin(xy))}{\partial x}&\dfrac{\partial(\sin(xy))}{\partial y}\end{bmatrix}=\begin{bmatrix}e^x&0\\y\cos(xy)&x\cos(xy)\end{bmatrix}

(b)

D f(x,y,z)=\begin{bmatrix}\dfrac{\partial(x-y)}{\partial x}&\dfrac{\partial(x-y)}{\partial y}&\dfrac{\partial(x-y)}{\partial z}\\\dfrac{\partial(y+z)}{\partial x}&\dfrac{\partial(y+z)}{\partial y}&\dfrac{\partial(y+z)}{\partial z}\end{bmatrix}=\begin{bmatrix}1&-1&0\\0&1&1\end{bmatrix}

(c)

Df(x,y)=\begin{bmatrix}y&x\\1&-1\\y&x\end{bmatrix}

(d)

Df(x,y,z)=\begin{bmatrix}1&0&1\\0&1&0\\1&-1&0\end{bmatrix}

5 0
3 years ago
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