Hello from MrBillDoesMath!
Answer:
x = 1/2 (1 +\- i sqrt(23))
Discussion:
x \3x - 2 = (x/3)*x - 2 = (x^2)/3 - 2 (*)
1 \3x - 4 = (1/3)x - 4 (**)
(*) = (**) =>
(x^2)/3 -2 = (1/3)x - 4 => multiply both sides by 3
x^2 - 6 = x - 12 => subtract x from both sides
x^2 -x -6 = -12 => add 12 to both sides
x^2-x +6 = 0
Using the quadratic formula gives:
x = 1/2 (1 +\- i sqrt(23))
Thank you,
MrB
Answer:
The answer is simple it would be the 3rd one(2nd row to the left)
Answer:
<h2>= 1.268</h2>
Step-by-step explanation:
= (3 + √3) (2 - √3)
= 6 - 3√3 + 2√3 - 3
= 3 - 3√3 + 2√3
= 3 - √3 (3 - 2)
= 3 - √3
= 3 - 1.732 ...... (√3 = 1.732)
= 1.268
54 cubes would fit in box one
<span>The perimeter is 14.47
Since you have 3 vertices, the polygon you have is a triangle. The sides of the triangle will be XY, XZ, and YZ. Just use the pythagorean theorem to calculate the length of each side and then add the lengths together for the result.
Side XY = sqrt( (-1-3)^2 + (3-0)^2) = sqrt(16+9) = sqrt(25) = 5
Side XZ = sqrt ( (-1-(-1))^2 + (3-(-2))^2) = sqrt(0+25) = sqrt(25) = 5
Side YZ = sqrt( (3-(-1))^2 + (0-(-2))^2) = sqrt(16 + 4) = sqrt(20) = 4.47
Now add the length of each side together
5 + 5 + 4.47 = 14.47</span>
